1-H NMR spectroscopy tool will be used for distinguishing a sample of 1,2,2-tribromopropane from 1,1,2-tribromopropane.
The preferred method for determining or validating the structure of organic molecules or those containing protons is H NMR. When compared to other nuclei, a solution-state proton spectrum may be obtained relatively quickly, and it contains a wealth of knowledge regarding a compound's structure.
It can be calculated by simply counting the number of unique hydrogens on one side of the symmetry plane will give you the count of signals individual molecules emit in a 1H NMR spectrum.
Therefore, 1-H NMR spectroscopy tool will be used for distinguishing a sample of 1,2,2-tribromopropane from 1,1,2-tribromopropane.
To know more about 1-H NMR spectroscopy
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Umm what kind of question is that but i think gain lol
the branch of science that deals with the identification of the substances of which matter is composed; the investigation of their properties and the ways in which they interact, combine, and change; and the use of these processes to form new substances.the branch of science that deals with the identification of the substances of which matter is composed; the investigation of their properties and the ways in which they interact, combine, and change; and the use of these processes to form new substances.
Explanation:
equations to note:
density= mass/volume
mass= volume *density
volume= mass/density
you have a volume- 8.33cm3
you have a density- 2.07 g/cm3
Answer:
8.33cm3 * 2.07g/cm3= 17.24g
mass= 17.24g
Answer:
872.28 kJ/mol
Explanation:
The heat released is:
ΔH = C*ΔT
where ΔH is the heat of combustion, C is the heat capacity of the bomb plus water, and ΔT is the rise of temperature. Replacing with data:
ΔH = 9.47*5.72 = 54.1684kJ
A quantity of 1.922 g of methanol in moles are:
moles = mass / molar mass
moles = 1.992/32.04 = 0.0621 mol
Then the molar heat of combustion of methanol is:
ΔH/moles = 54.1684/0.0621 = 872.28 kJ/mol
