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shepuryov [24]
3 years ago
10

Christina is studying a sugar molecule known as ribose. The molar mass of ribose is 150r/mole. What is the mass of 5.0 moles of

ribose? a. 150.23 O 6.13 x 10-33 O c. 148.8 g O d.306 750 g Oe
Chemistry
1 answer:
seraphim [82]3 years ago
6 0

Answer : The mass of 5.0 moles of ribose is 750 grams.

Explanation : Given,

Moles of ribose = 5.0 moles

Molar mass of ribose = 150 g/mole

Formula used :

\text{Mass of ribose}=\text{Moles of ribose}\times \text{Molar mass of ribose}

Now put all the given values in this formula, we get:

\text{Mass of ribose}=5.0mole\times 150g/mole=750g

Therefore, the mass of 5.0 moles of ribose is 750 grams.

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A gas has a volume of 5.00 L at 20 degrees Celsius. What is the volume of gas at 150 degrees Celsius.
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Make V₂ the subject of the equation

V₂ = (V₁×T₂)/T₁................. Equation 2

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3 years ago
You have 500.0 ml of a buffer solution containing 0.30 m acetic acid (ch3cooh) and 0.20 m sodium acetate (ch3coona). what will t
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First, we should get moles acetic acid = molarity * volume

                                                                =0.3 M * 0.5 L

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then, we should get moles acetate = molarity * volume

                                                           = 0.2 M * 0.5L

                                                           = 0.1 mol

then, we have to get moles of OH- which added:

moles OH- = molarity  * volume

                   = 1 M    * 0.02L

                  = 0.02 mol

when the reaction equation is:


                 CH3COOH  +  OH-  → CH3COO-   +  H2O


moles acetic acid after adding OH- = (0.15-0.02) 
                                             
                                                            =  0.13M                                       

moles acetate after adding OH- =  (0.1 + 0.02)

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∴[acetic acid] = moles acetic acid after adding OH- / total volume

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when we have Ka = 1.8 x 10^-5

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        = -㏒ 1.8 x 10^-5

       = 4.7

So by substitution:

∴ PH = 4.7 + ㏒[acetate/acetic acid]

         = 4.7 + ㏒(0.23/0.25)

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