Write the equation in slope-intercept form for a line that has a y-intercept of -3 and a slope of 6. Use no spaces in your equat
1 answer:
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Answer:
option C
Step-by-step explanation:
f(x)=-0.08x(x^2-11x+18)
Factor the parenthesis and find out the x intercepts
(x^2-11x+18)
We find out two factors whose product is 18 and sum is -11
-9 and -2 gives us product 18
-9 -2 gives us sum -11
(x^2-11x+18) =(x-9)(x-2)
f(x)=-0.08x(x^2-11x+18)
f(x)= -0.08x(x-9)(x-2)
set f(x) =0 and solve for x
-0.08x(x-9)(x-2) =0
-0.08x =0, so x=0
x-9 = 0 , so x=9
x-2 =0 , so x=2
x intercepts are (0,0) (2,0) and (9,0)
x intercepts are not repeating
so the graph crosses x -axis at x=0, 2,9
option C is correct
The graph is attached below4
