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Irina18 [472]
4 years ago
9

Question 2 How many significant figures does the number have? 23.0702

Chemistry
1 answer:
Pavlova-9 [17]4 years ago
7 0
The number 23.0702 has 6 significant figures.

To answer this, you must have the rules for significant figures,

1. All non-zero numbers ARE significant
2. Zeros between two non-zero digits ARE significant
3. Leading zeros are NOT significant
4. Trailing zeros are ONLY significant if the number has a decimal point

The number 23.0702 has 4 non-zero numbers(rule 1), and both zeros are between two non-zero digits(rule 2). Since all 6 figures in the number 23.0702 are significant, the number 23.0702 has 6 significant figures.
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Two or more atoms chemically bonded together are called
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A compound is "a substance formed when two or more chemical elements are chemically bonded together." There are two main types of chemical bonds: covalent and ionic.

Explanation:

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8 0
3 years ago
Redox titrations are used to determine the amounts of oxidizing and reducing agents in solution. For example, a solution of hydr
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Answer:

0.374 g

Explanation:

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Since both the molarity and the volume allows us to know the moles of potassium permanganate, and we already have the balanced chemical reaction, the stoichiometric procedure that is attached in the picture, is developed to substantiate the the titrated mass of hydrogen peroxide was 0.374 g.

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4 years ago
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Different isotopes of an element generally have the same physical and chemical properties because they have the same numbers of protons and electrons.

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3 years ago
If helium effuses through a porous barrier in 1.34 min, how much time (in min) would it take the same amount of ammonia to effus
timofeeve [1]

Answer:

The time taken the same amount of ammonia to effuse through the same barrier under the same conditions is 2.76 minutes.

Explanation:

Let the volume of the helium gas be = V

Time taken by the helium gas = t = 1.34 min

Effusion rate of helium gas = R=\frac{V}{1.34 min}

If V volume of ammonia effuse through same porous barrier the effusion rate of ammonia gas will be given as:

R'=\frac{V}{t'}

Using Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}

Molar mass of helium gas = M = 4 g/mol

Molar mass of ammonia gas = M' = 17 g/mol

\frac{R}{R'}=\sqrt{\frac{M'}{M}}

\frac{\frac{V}{1.34 min}}{\frac{V}{t'}}=\sqrt{\frac{17 g/mol}{4 g/mol}}

t'=1.34 min\times \sqrt{\frac{17 g/mol}{4 g/mol}}=2.76 min

The time taken the same amount of ammonia to effuse through the same barrier under the same conditions is 2.76 minutes.

8 0
3 years ago
Which reaction is an example of heterogeneous catalysis?
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Answer:

Explanation:

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Ammonia synthesis (Haber–Bosch process) N2 + H2, NH3

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Hydrogen production by Steam reforming CH4 + H2O, H2 + CO2

Ethylene oxide synthesis C2H4 + O2, C2H4O

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