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3 years ago

Which reaction is an example of heterogeneous catalysis?

Chemistry

1 answer:

lesya692 [45]3 years ago

5 0

Answer:

Explanation:

Industrial examples

Process Reactants, Product(s)

Ammonia synthesis (Haber–Bosch process) N2 + H2, NH3

Nitric acid synthesis (Ostwald process) NH3 + O2, HNO3

Hydrogen production by Steam reforming CH4 + H2O, H2 + CO2

Ethylene oxide synthesis C2H4 + O2, C2H4O

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The energy stored in foods and fuels is?

elixir [45]

Chemical potential energy

5 0

3 years ago

When you finish using the compound brightfield microscope, what should you have your lab instructor do?

ira [324]

Answer:

To check if it's properly cleaned.

Explanation:

When you finish using a microscope, you have to take out all your samples you were using and make sure it is completely clean so that no further contamination affects future sample analysis.

Also when you begin to use it, make sure it is clean so that when you analyze your sample(s) are free from other unexpected agents.

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4 years ago

4. A student started with a 0.032 g sample of copper which he took through the series of reactions described in this experiment.

Elodia [21]

Answer:

$Y=48.6\%$

Explanation:

Hello,

In this case, we can consider the following chemical reaction for the oxidation of copper which only occurs at high temperatures:

$2Cu+O_2\rightarrow 2CuO$

In such a way, for 0.032 grams of copper, the following grams of copper (II) oxide (black product) are yielded:

$m_{CuO}=0.032gCu*\frac{1molCu}{63.546gCu} *\frac{2molCuO}{2molCu}*\frac{79.546gCuO}{1molCuO} =0.078gCuO$

Therefore, the percent yield is:

$Y=\frac{0.038g}{0.078g}*100\%\\ \\Y=48.6\%$

Best regards.

6 0

3 years ago

A chemist determined by measurements that 0.030 moles of barium participated in a chemical reaction. Calculate the mass of bariu

schepotkina [342]

Answer: 4.1 g of barium precipitated.

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar Mass}}$

Given : moles of barium = 0.030

Molar mass of barium = 137 g/mol

$0.030=\frac{x}{137}$

x= 4.1 g

Thus there are 4.1 g of barium that precipitated.

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3 years ago

What is the Mass in grams of 3.1 mol of mercury

nasty-shy [4]

Answer: 200.59 grams

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3 years ago