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BaLLatris [955]
3 years ago
14

Newtons law of garvitation is known as universal law. Why​

Physics
1 answer:
xeze [42]3 years ago
5 0

Answer:

It is called so because it is applicable on all bodies having mass, and the bodies will be governed by the same law, that is newton's law of gravitation. Thus, as it is applicable universally, it is called as universal law.

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Will upvote!!!!
juin [17]
D. potential energy, because there is a bunch of water pent up, essentially stationary, waiting to roll down the steep mountain from the peak, so to say. if the dam were to be removed it would become kinetic.
4 0
3 years ago
Read 2 more answers
Find the intensity of a 55 dB sound given I 0=10^-12W/m^2
MakcuM [25]

Answer:

3.16 × 10^{-7} W/m^{2}

Explanation:

β(dB)=10 × log_{10}(\frac{I}{I_{0} })

I_{0}=10^{-12} W/m^{2}

β=55 dB

Therefore plugging into the equation the values,

55=10 log_{10}(\frac{I}{ [tex]10^{-12}})[/tex]

5.5= log_{10}(\frac{I}{ [tex]10^{-12}})[/tex]

10^{5.5}= \frac{I}{10^{-12} }

316227.76×10^{-12}= I

I= 3.16 × 10^{-7} W/m^{2}

5 0
3 years ago
A wheel has a rotational inertia of 16 kgm2. Over an interval of 2.0 s its angular velocity increases from 7.0 rad/s to 9.0 rad/
german

Answer:

<h2>128.61 Watts</h2>

Explanation:

Average power done by the torque is expressed as the ratio of the workdone by the toque to time.

Power = Workdone by torque/time

Workdone by the torque = \tau \theta = I\alpha * \theta

I is the rotational inertia = 16kgm²

\theta = angular\ displacement

\theta = 2 rev = 12.56 rad

\alpha \ is \ the\ angular\ acceleration

To get the angular acceleration, we will use the formula;

\alpha = \frac{\omega_f^2- \omega_i^2}{2\theta}

\alpha = \frac{9.0^2- 7.0^2}{2(12.54)}\\\alpha = 1.28\ rad/s^{2}

Workdone by the torque = 16 * 1.28 * 12.56

Workdone by the torque = 257.23 Joules

Average power done by the torque = Workdone by torque/time

=  257.23/2.0

= 128.61 Watts

8 0
3 years ago
An _________ is a light ray moving toward a boundary.
Sveta_85 [38]

When A Light Ray Hits A Boundary,,,,, it is called refraction.

6 0
3 years ago
A dog, with a mass of 10.0 kg, is standing on a flatboat so that he is 22.5 m from the shore. He walks 7.8 m on the boat toward
marissa [1.9K]

Answer:16.096

Explanation:

Given

mass of dog\left ( m_d\right )=10kg

mass of boat\left ( m_b\right )=46kg

distance moved by dog relative to ground=x_d

distance moved by boat relative to ground=x_b

Distance moved by dog relative to boat=7.8m

There no net force on the system therefore centre of mass of system remains at its position

0=m_d\times x_d+m_b\dot x_b

0=10\times x_d+46\dot x_b

x_d=-4.6x_b

i.e. boat will move opposite to the direction of dog

Now

|x_d|+|x_b|=7.8

substitutingx_dvalue

5.6|x_b|=7.8

|x_b|=1.392m

|x_d|=6.4032m

now the dog is  22.5-6.403=16.096m from shore

4 0
3 years ago
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