Question

A machine raised a load of 360N through a distance of 0.2m. The effort, a force of 50N moved 1.8m during the process. Calculate the efficiency of the machine.
Select one:
a. 40%
b. 100%
c. 80%
d. 60%

Answer 1

Answer:

c. 80%

Explanation:

Given;

load raised by the machine, L = 360 N

distance through which the load was raised, d = 0.2 m

effort applied, E = 50 N

distance moved by the effort, e = 1.8 m

The efficiency of the machine is calculated as follows;

$Efficiency = \frac{ 0utput \ work }{1nput \ work} \times 100\% \\\\Efficiency = \frac{Load \ \times \ distance \ moved \ by \ load }{Efort \ \times \ distance \ moved \ by \ effort} \times 100\%\\\\Efficiency = \frac{360 \times 0.2}{50 \times 1.8} \times 100\%\\\\Efficiency =80\%$

Therefore, the efficiency of the machine is 80%