Points N and R both lie on circle O. Line segment RQ is tangent to the circle at point R.
2 answers:
Answer:
Perimeter ΔRON = 18.66 units
Step-by-step explanation:
Complete Question has these information given as well:
- Circle with center O
- RN = QN
- RQ =
- ON = 5 units
- RQ is tangent
<em><u>Now, we draw an image according to the information given. THe image drawn is attached.</u></em>
<em><u /></em>
Looking at the figure, we can say the perimeter of triangle RON would be:
RON = OR + ON + RN
We know according to tangent theorem, QN = QR
RN is equal to that as well and RN =
Now,
OR and ON is the radius, which is "5"
Perimeter of RON = 5 + 5 + = 10 +
= 18.66 units
<u>Perimeter ΔRON = 18.66 units</u>
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Answer:
(1,1)
Step-by-step explanation:
we have
----> equation A
----> equation B
we know that
The solution of the system of equations is the intersection point both graphs
The intersection point both graphs is the point (1,1)
see the given graph
therefore
The solution is the point (1,1)
Remember that
if a ordered pair is a solution of a system of equations then the ordered pair must satisfy both equations of the system
<u><em>Verify</em></u>
Substitute the value of x=1 and y=1 in each equation and analyze the result
<em>Equation A</em>
---> is true
so
The ordered pair satisfy the equation A
<em>Equation B</em>
---> is true
so
The ordered pair satisfy the equation B
therefore
The ordered pair (1,1) is a solution of the system because satisfy both equations