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Maru [420]
3 years ago
5

Write number then solution!!!!!!!!!!!

Chemistry
2 answers:
vivado [14]3 years ago
7 0

Answer:

1- waxing gibbous

2- third quarter

3- waxing crescent

4- full moon

5- waning crescent

6- new moon

7- first quarter

8- waning gibbous

Explanation:

hope that helps

Zielflug [23.3K]3 years ago
6 0
Pain and suffering

Pain and suffering

Pain and suffering
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Decide which element probably forms a compound with oxygen that has a chemical formula most and least similar to the chemical fo
mafiozo [28]

Answer:

Most similar   -----  Lithium

Least similar   ----  Nitrogen

Explanation:

Cesium is an element on the periodic with the atomic number 133. It lies in group 1 (i.e., the alkali metals) and period 6 on the periodic table. The oxidation state of group 1 metals is +1. Cesium forms an oxide with oxygen as  Cs_2O.

The most similar compound to this chemical compound is Lithium because Lithium happens to be in the same group one metal with Cesium and forms the compound Li_2O with the oxygen

The least similar compound nitrogen due to fact that it is an oxide that is covalent in nature and lies between-group 3 -17  to form an NO_2 with oxygen.

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3 years ago
Samantha is using a lever to lift a rock. To life the rock most easily, where should she apply force to the lever
Inessa [10]

Answer:

On the opposite side of the rock.

Explanation:

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4 years ago
What would be a likely climatic outcome of rising ocean temperatures?
Kay [80]
I think your answer is D. However I’m not 100% sure.
7 0
3 years ago
There can be many different colors of beetles within the same species.This is an example of
azamat

Answer:

natural selection

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6 0
2 years ago
How many molecules of CBr4 are in 250 grams of CBr4
Kazeer [188]

Answer:- 4.54*10^2^3 molecules.

Solution:- The grams of tetrabromomethane are given and it asks to calculate the number of molecules.

It is a two step unit conversion problem. In the first step, grams are converted to moles on dividing the grams by molar mass.

In second step, the moles are converted to molecules on multiplying by Avogadro number.

Molar mass of CBr_4  = 12+4(79.9)  = 331.6 g per mol

let's make the set up using dimensional analysis:

250g(\frac{1mol}{331.6g})(\frac{6.022*10^2^3molecules}{1mol})

= 4.54*10^2^3 molecules

So, there will be 4.54*10^2^3 molecules in 250 grams of CBr_4 .


8 0
3 years ago
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