Using SUVAT
U = 0 m/s
A = g = 9.8 ms^-2
T = 3.41 s
S = ?
s = ut + 1/2at^2
s = (0)(3.41) + 1/2(9.8)(3.41^)
s = 1/2(9.8)(3.41^2)
s = 1/2(9.8)(11.6281)
s = 56.97769 m
You can tell if vector is an unit because it has something to do with taking the magnitude of the vector.
also has a length 1. thus you should use pythagoras to check.
Hope this help
Answer:
Incomplete question
Complete question:
a constant force acts upon an object, the acceleration of the object varies inversely with its mass. When a certain constant force acts upon an object with mass 44kg , the acceleration of the object is 4m/s². If the same force acts upon another object whose mass is 11kg what is this object's acceleration?
Answer: 8m/s²
Explanation:
From the statement we deduced that acceleration varies inversely with mass where force was kept constant.
Therefore,
F/m = a or F = ma
For the first statement, substituting the mass and acceleration gives:
F = 44 x 4 = 88N
Applying the force above to the second mass gives us:
a = 88/11 = 8m/s²
The energy transferred to the spring is given by:

where
k is the spring constant
x is the elongation of the spring with respect its initial length
Let's convert the data into the SI units:


so now we can use these data inside the equation ,to find the energy transferred to the spring: