Answer:
The expected value of the winnings for a single-ticket purchase is -$1.0016.
Step-by-step explanation:
The total number of tickets sold is, <em>N</em> = 1250.
Cost of one ticket is, $4.
Let <em>X</em> = amount of prize.
The prize distribution is as follows:
1 Grand price = $3000
1 Second prize = $450
10 Third prize = $25
The expected value <em>X</em> can be computed using the formula:

Compute the probability distribution of <em>X</em> as follows:
Prize Amount (X) P (X) x · P (X)
1 Grand prize $3000

1 Second prize $450

10 Third prize $25

No prize -$4

TOTAL 1.0000 -1.0016
Thus, the expected value of the winnings for a single-ticket purchase is -$1.0016.
Answer:
Step-by-step explanation:
jjjjjjjjjjjjj
3 & 6 - LCM = 3. 3's multiples are 3, 6, 9,12, 16, etc. 6's multiples are 6, 12, 18, etc. therefore, the least common multiple is 6.
GCF - 3's factors are 1, 3, and 6's factors 1, 2, 3. so the greatest common factor is 3.
4\9=.444444444
answer=choice D
Answer:
Horizontal distance = 1.98 m (Approx)
Step-by-step explanation:
Given:
Height = 2.5 m
Speed v = 2.8 m/s
Find:
Horizontal displacement
Computation:
s = ut + (1/2)gt²
2.5 = (1/2)(9.8)t²
t² = 0.5102
t = 0.7079 s
Horizontal distance = (v)(t)
Horizontal distance = (2.8)(0.7079)
Horizontal distance = 1.98 m (Approx)