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serious [3.7K]
3 years ago
15

Dead leaves on the forest floor become new soil through the actions of _____.

Chemistry
2 answers:
laila [671]3 years ago
5 0
I believe the answer is Decomposition. They become new soil through decomposers decomposing it, and making it soil.
~Silver

dmitriy555 [2]3 years ago
4 0

Decomposers break down different organic matter into the soil.

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I think it is b.astrology

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Can you make the particles of any of the substances stop moving?
ser-zykov [4K]

The particles cannot move around at all. The particles are, however, still in motion.

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4 years ago
What is the value of Avogadro's constant?​
diamong [38]

Answer:

6.02214154 x 1023

Explanation:

6 0
3 years ago
How much (Q) heat is needed to melt 35 g of iodine? Hf = 61.7 J/g.
aev [14]

Taking into account the definition of calorimetry and latent heat, a heat of 2159.5 J is needed to melt 35 g of iodine.

<h3>Calorimetry</h3>

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

<h3>Latent heat</h3>

Latent heat is defined as the energy required by a quantity of substance to change state.

When this change consists of changing from a solid to a liquid phase, it is called heat of fusion and when the change occurs from a liquid to a gaseous state, it is called heat of vaporization.

The heat Q that is necessary to provide for a mass m of a certain substance to change phase is equal to

Q = m×L

where L is called the latent heat of the substance and depends on the type of phase change.

<h3>Heat needed to melt iodine</h3>

In this case, you know:

  • m= 35 g
  • L=61.7 \frac{J}{g}

Replacing in the definition of latent heat:

Q= 35 g× 61.7 \frac{J}{g}

Solving:

<u><em>Q=2159.5 J</em></u>

Finally, a heat of 2159.5 J is needed to melt 35 g of iodine.

Learn more about calorimetry:

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brainly.com/question/24988785

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#SPJ1

8 0
2 years ago
How much sucrose (g) do you need to weight in order to prepare 19.16 g of a 13.1 % (weight percent) solution?
Nonamiya [84]
<span>2.51 grams
   You want to prepare 19.16 g of some solution which will have 13.1% of it's mass being sucrose. So we just need to perform some simple multiplication: 19.16g * 0.131 = 2.50996g
   Rounding to 3 significant figures gives 2.51 g.</span>
3 0
3 years ago
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