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Damm [24]
3 years ago
8

What is the equation for momentum? Please help need answer ASAP.

Physics
2 answers:
Shkiper50 [21]3 years ago
7 0

Answer:

moment = mass×velocity

Explanation:

p =momentum

m =mass

v= velocity

p=mv

hope this helped

Leona [35]3 years ago
3 0
Momentum is mass in motion and only applies to objects in motion. It's a term that describes a relationship between the mass and velocity of an object, and we can see this when it is written in equation form, p = mv, where p is momentum, m is mass in kg and v is velocity in m/s.
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Owen throws a baseball straight upward. We can ignore air resistance.
dusya [7]

Answer:

The acceleration of the ball is constant and equal to -9.81 m/s² (acting downwards)

The velocity of the ball reduces at a constant rate with time on its way up

Explanation:

The motion of the ball upwards is described by the following equation;

v = u - g × t

v² = u² - 2 × g × s

Where;

v = The final velocity of the ball

u = The initial velocity of the ball

g = The acceleration due to gravity = Constant

s = The height of the bass after a given time, t

t = The time in which the ball is rising

Therefore, the acceleration of the ball = The acceleration due to gravity  (Constant) = -9.81 m/s²↓

From v = u - g × t = u - 9.81 × t , the velocity of the ball reduces at a constant rate with time on its way up.

7 0
3 years ago
If a thief jumps from the tried floor of a house while holding a box on
Ksju [112]
What do you mean? it doesn't make sense
7 0
3 years ago
Read 2 more answers
An object of mass m is traveling around a circle of radius v. What happens to the centripetal force if the radius is cut in half
german

Answer:

Centripetal force doubles

Explanation:

Since centripetal force is given by

F=\frac {mv^{2}}{r}

Where F is the centripetal force, m is the mass, v is the centripetal velocity and r is circle radius.

When the radius is reduced to half then the centripetal force will be

F=\frac {mv^{2}}{0.5r}=\frac {2mv^{2}}{r}

Evidently, the centripetal force is doubled compared to the initial.

Note that while the question gives letter v for radius, I used v for velocity and r for radius since these are the standard letters for abbreviating formula of centripetal force.

7 0
3 years ago
An open-end mercury manometer is connected to a low-pressure pipeline that supplies a gas to a laboratory. Because paint was spi
almond37 [142]

Answer:

A. Using

Pgauge= Pmanometer

And we know that

Pgauge= deta(hpg)

So deta h = Pgauge/density x g

So

= 7.5(6894.76/1psig)/ 13.6*10^3*9.8m/s²)

= 387.9mm

So to find height of pipe connected to the pipe we say

= h -deta h

= 900-387.97mm

=512.02mm

B. We use manometry principle

Pgas+density xg(25*10^3)-PX density{h-(H-0.25)=0

So

Finally Pgas= 6.54psig

3 0
3 years ago
Suppose you drop a 10-pound weight and a 5-pound weight on the Moon, both from the same height at the same time. What will happe
Murljashka [212]

Answer:

Both will hit the ground at the same time.

3 0
2 years ago
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