Answer:
The acceleration of the ball is constant and equal to -9.81 m/s² (acting downwards)
The velocity of the ball reduces at a constant rate with time on its way up
Explanation:
The motion of the ball upwards is described by the following equation;
v = u - g × t
v² = u² - 2 × g × s
Where;
v = The final velocity of the ball
u = The initial velocity of the ball
g = The acceleration due to gravity = Constant
s = The height of the bass after a given time, t
t = The time in which the ball is rising
Therefore, the acceleration of the ball = The acceleration due to gravity (Constant) = -9.81 m/s²↓
From v = u - g × t = u - 9.81 × t , the velocity of the ball reduces at a constant rate with time on its way up.
What do you mean? it doesn't make sense
Answer:
Centripetal force doubles
Explanation:
Since centripetal force is given by

Where F is the centripetal force, m is the mass, v is the centripetal velocity and r is circle radius.
When the radius is reduced to half then the centripetal force will be

Evidently, the centripetal force is doubled compared to the initial.
Note that while the question gives letter v for radius, I used v for velocity and r for radius since these are the standard letters for abbreviating formula of centripetal force.
Answer:
A. Using
Pgauge= Pmanometer
And we know that
Pgauge= deta(hpg)
So deta h = Pgauge/density x g
So
= 7.5(6894.76/1psig)/ 13.6*10^3*9.8m/s²)
= 387.9mm
So to find height of pipe connected to the pipe we say
= h -deta h
= 900-387.97mm
=512.02mm
B. We use manometry principle
Pgas+density xg(25*10^3)-PX density{h-(H-0.25)=0
So
Finally Pgas= 6.54psig