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marissa [1.9K]
3 years ago
9

Under what conditions would a rope remain in equilibrium during a tug of war

Physics
2 answers:
Andrei [34K]3 years ago
7 0
<h3>Answer;</h3>

B)  When the net force acting on the rope is zero.  

<h3><u>Explanation;</u></h3>
  • <u><em>Equilibrium refers to a state of balance where there is no net force. The forces acting at point in equilibrium are opposite and equal.</em></u>
  • <u><em>Therefore, for a body at equilibrium the vector sum of all the forces acting on that body must be zero and also the vector sum of torques on the body must be zero</em></u>.
  • <em><u>In a tug of war for example, the equilibrium will be achieved if the two teams involved on either side apply equal forces in opposite direction, such that there will be no net force on the rope, that is the net force on the rope is zero.</u></em>
miskamm [114]3 years ago
3 0
When the teams on each end of the rope exert exactly the
same force ... in opposite directions ... the net force on the
rope is zero, and it doesn't accelerate in either direction.
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Correct answer is D.

Explanation:
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B) is not correct answer because this theory could be replaced if some evidence show that some other theory is more likely to be correct.

C) is not correct answer because the study has been done on other nebulas in our galaxy. There are many nebulas and by obserwing them this theory was developed.
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3 years ago
The logarithm of x, written log(x), tells you the power to which you would raise 10 to get x. So, if y=log(x), then x=10^y. It i
fomenos

To solve this problem it is necessary to apply the rules and concepts related to logarithmic operations.

From the definition of logarithm we know that,

Log_{10}(10) = 1

In this way for the given example we have that a logarithm with base 10 expressed in the problem can be represented as,

log_{10}(1,000,000)

We can express this also as,

log_{10}(10^6)

By properties of the logarithms we know that the logarithm of a power of a number is equal to the product between the exponent of the power and the logarithm of the number.

So this can be expressed as

6*log_{10}(10)

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Show the weight of the ladder and draw the missing Frictional force.
madreJ [45]
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So to find the weight, divide the 100N <em>normal</em> force by earths gravitational acceleration, 9.8m/s^2

W =  \frac{N}{g}  =  \frac{100N}{9.8m/s^{2}} =  \frac{100}{9.8} = 10.2kg


Then;
Draw an arrow at the base of the ladder pointing towards the wall with a value of 30N, to show the frictional force.
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3 years ago
A boxed 14.0 kg computer monitor is dragged by friction 5.50 m up along the moving surface of a conveyor belt inclined at an ang
adell [148]

Answer:

A boxed 14.0 kg computer monitor is dragged by friction 5.50 m up along the moving surface of a conveyor belt inclined at an angle of 36.9 ∘ above the horizontal. The monitor's speed is a constant 2.30 cm/s.

how much work is done on the monitor by (a) friction, (b) gravity

work(friction) = 453.5J

work(gravity) = -453.5J

Explanation:

Given that,

mass = 14kg

displacement length = 5.50m

displacement angle = 36.9°

velocity = 2.30cm/s

F = ma

work(friction) = mgsinθ .displacement

                      = (14) (9.81) (5.5sin36.9°)

                       = 453.5J

work(gravity)

= the influence of gravity oppose the motion of the box and can be pushing down, on the box from and angle of (36.9° + 90°)

= 126.9°

work(gravity) = (14) (9.81) (5.5cos126.9°)

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8 0
3 years ago
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