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e-lub [12.9K]
3 years ago
11

In the International System of Units, the basic unit for measuring mass is what

Physics
1 answer:
nadezda [96]3 years ago
3 0

Answer:

Kilograms (kg)

Explanation:

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A web page designer creates an animation in which a dot on a computer screen has a position of r⃗ =[ 4.50 cm +( 2.90 cm/s2 )t2]i
VMariaS [17]

Answer:

V = (5.8cm/s)i, (4.7cm/s)j

Explanation:

Given :

r⃗ =[ 4.50 cm +( 2.90 cm/s2 )t2]i^+( 4.70 cm/s )tj^

To obtain the average velocity (V)

V = (r2 - r1) / (t2 - t1)

To obtain r1 and r2, substitute t1 = 0 and t2 = 2 respectively in the equation above

r1 = [ 4.50 cm +( 2.90 cm/s2 ) 0]i^+( 4.70 cm/s )0 j

r1 = 4.50 cm + 0 + 0 = (4.50cm)i + 0j

r2 = [ 4.50 cm +( 2.90 cm/s2 )2²]i^+( 4.70 cm/s )2 j

r2 = 4.50cm + (2.90 × 4)i + (4.70 × 2)j

r2 = (16.1cm)i + (9.4cm)j

V = [(16.1 - 4.50)i - (9.4 - 0)j] / 2 - 0

V = 11.6i / 2 ; 9.4j / 2

V = (5.8cm/s)i, (4.7cm/s)j

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3 years ago
Non living things in the ocean
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A person 1.8m tall stands 0.75m from a reflecting globe in a garden.
Maru [420]

Answer:

1. The image of the person is 1.41 m, virtual and formed at the back of the surface of the globe.

2. The person's image is 3.38 m tall.

Explanation:

From the given question, object distance, u = 0.75 m, object height = 1.8 m, radius of curvature of the reflecting globe, r = 8 cm = 0.08 m.

f = \frac{r}{2} = \frac{0.08}{2} = 0.04 m

1. The image distance, v, can be determined by applying mirror formula:

\frac{1}{f} = \frac{1}{u} + \frac{1}{v}

\frac{1}{0.04} = \frac{1}{0.75} + \frac{1}{v}

\frac{4}{100} - \frac{75}{100} = \frac{1}{v}

\frac{1}{v} = \frac{4 - 75}{100}

  = - \frac{71}{100}

⇒ v = -\frac{100}{71}

      = - 1.41 m

The image of the person is 1.41 m, virtual and formed at the back of the surface of the globe.

2.  \frac{image distance}{object distance} = \frac{image height}{object height}

  \frac{1.41}{0.75} = \frac{v}{1.8}

v = \frac{2.538}{0.75}

  = 3.384

v = 3.38 m

The person's image is 3.38 m tall.

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