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hichkok12 [17]
3 years ago
6

Use the subtraction property of equality to complete this statement. If y = 3 and 8x + y = 12, then

Mathematics
2 answers:
Over [174]3 years ago
6 0
8x + y = 12 (substitute 3 for y) 
<span>8x + 3 = 12 </span>
<span>8x = 9 </span>
<span>x = 9/8 </span>

<span>If y = 3 and 8x + y = 12, then x = 9/8.

HOPE THIS HELPS!!</span>
MrRa [10]3 years ago
5 0
8x + 3 - 3 = 12 - 3               8x = 9             8x/8 = 9/8             x = 1.125
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Sunny_sXe [5.5K]

Answer:

f(x) = 3 \cdot 0.2^x

Step-by-step explanation:

f(x) = 3 \cdot 0.2^x


Domain of f: "What values of x can we plug into this equation?" This makes sense for all real numbers so the domain is \mathbb{R}

Range of f: "What values of f(x) can we get out of the function?" From the graph we see we can get any real number greater than 0 out of the function by choosing a suitable x-value in the domain. The range is therefore (0, \infty).

Continuity: Since the graph is one, unbroken curve (i.e. a curve that can be drawn in one movement without taking your pen off the paper). We see that "roughly speaking" the function is continuous.

Increasing or decreasing behaviour: For all x in the domain, as x increases, f(x) decreases. This means the function exhibits decreasing behaviour.

Symmetry: It is clear to see the graph of f(x) has no symmetry.

Boundedness: Looking at the graph we see it is unbounded above as when we choose negative values, the graph of f(x) explodes upwards exponentially. Choose a value of x, plug it in, next choose (x-1), plug this in and we observe f(x-1) > f(x) for all x in the domain.

The function is however bounded below by 0: no value of x in the domain exists which satisfies f(x) < 0.

Extrema: As far as I can tell, there are no turning points on the curve. (Is this what you mean by extrema?)

Asymptotes: Contrary to the curve's appearance, there are no vertical asymtotes for this curve. The negative-x portion of the curve is just growing so quickly it appears to look like an asymptote. There is a value of f(x) for all x<0. There is however a horizontal asymtote: y=0.

End behaviour: As x \rightarrow \infty, f(x) \rightarrow 0. As x \rightarrow -\infty, f(x) \rightarrow +\infty

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3 years ago
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1 year ago
A factory can work its employees no more than 6 days a week, and no less than 2 days per
Molodets [167]

Answer:

Step-by-step explanation:

Answer: A.) 2 <= X <= 6

B.) 13 < = X < = 39

Step-by-step explanation:

Given that a factory can work its employees no more than 6 days a week, that is, less than or equal to 6 days a week

And also, no less than 2 days per week. That is, greater than or equal to 2 day a week.

Let X represent the number of days an employee can work per week.

According to the first statement,

X < = 6

According to the second statement,

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An inequality to represent the range of days an employee can work will be

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To represent the range in hours, first convert the number of days to hour. Given that an employee can work

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6 0
3 years ago
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Step-by-step explanation:

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Answer:

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