Activity_Mass_Balance_Recycle
1 answer:
Answer:
m₁ = 1720
m₂ = 413.46
m₃ = 586.54
mr = 720
Explanation:
Draw a diagram. Sea water (1000 lb/h, 3.1% salt) is mixed with the recycled brine (mr, 5.25% salt) to create the inlet stream (m₁, 4.0% salt). This inlet stream is fed into the osmosis cell. The osmosis cell produces desalinated water (m₂, 500 ppm) and brine tailings. Part of the tailings is recycled (mr, 5.25% salt), and the rest is removed (m₃, 5.25%).
The mass of water is conserved, so:
1000 + mr = m₁
m₁ = mr + m₂ + m₃
The mass of salt is conserved, so:
0.031 (1000) + 0.0525 mr = 0.040 m₁
0.040 m₁ = 0.0525 mr + 0.0005 m₂ + 0.0525 m₃
Four unknown variables, and four equations. We can use the first and third to find mr and m₁.
0.031 (1000) + 0.0525 mr = 0.040 (1000 + mr)
31 + 0.0525 mr = 40 + 0.040 mr
0.0125 mr = 9
mr = 720
m₁ = 1720
Now we can use these values and the second and fourth equations to solve for the remaining variables.
1720 = 720 + m₂ + m₃
0.040 (1720) = 0.0525 (720) + 0.0005 m₂ + 0.0525 m₃
1000 = m₂ + m₃
68.8 = 37.8 + 0.0005 m₂ + 0.0525 m₃
68.8 = 37.8 + 0.0005 m₂ + 0.0525 (1000 − m₂)
68.8 = 37.8 + 0.0005 m₂ + 52.5 − 0.0525 m₂
0.052 m₂ = 21.5
m₂ = 413.46
m₃ = 586.54
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Answer: Option (c) is correct answer.
Explanation:
The given reaction equation is as follows.
The number of atoms on reactant side are as follows.
- Fe = 2
- O = 3
- H = 1
- Cl = 1
The number of atoms on product side are as follows.
- Fe = 1
- O = 1
- H = 2
- Cl = 3
Therefore, in order to balance the equation we will balance the number of atoms in both reactant and product side.
Since number of Fe atoms in reactant side is 2, therefore, multiply by 2 in the product side.
Number of O atoms in reactant side is 3, therefore, multiply by 3 in the product side.
Now, the number of H atoms on product side is 6, therefore, multiply HCl by 6 in the reactant side.
The number of chlorine atoms on both reactant and product side equals 6.
Thus, the equation will become as follows.
Hence, the equation is balanced.