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kramer
3 years ago
6

Suppose a 1.2 m antenna is installed on top of a building that is 225 m tall,

Physics
1 answer:
vazorg [7]3 years ago
7 0

Answer: 226.2 m

Explanation:

If we want to find the new total height H of the building, we have to add to its initial height h_{B}=225m the height of the antenna h_{A}=1.2m, as follows:

H=h_{B}+h_{A}

H=225m+1.2m

Then:

H=226.2m This is the new total height of the building.

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A mass spectrometer is used to examine the isotopes of uranium. Ions in the beam emerge from the velocity selector at a speed of
Vsevolod [243]

Answer:

0.2 m

Explanation:

magnetic force = centripetal force

qvB = mv² / r

cancel v on both side and make r subject of the formula

r₁ = mv / qB where m = mass of ion, v = velocity of the ion

r₁  = ( 235 × 1.67 × 10⁻²⁶ × 2.81 × 10⁵) / ( 1.6 × 10⁻¹⁹ × 0.605 T) = 1139.24 × 10⁻² = 11.4 m

r₂ = ( 238 × 1.67 × 10⁻²⁶ × 2.81 × 10⁵) / ( 1.6 × 10⁻¹⁹ × 0.605 T)  = 1153.78 × 10⁻² = 11.5 m

D, distance between the impact points formed = d₂ - d₁ where d₂ and d₁ represent the diameters of the charged ions

D = (2 × 11.5 m) - ( 2 × 11.4) = 2 ( 11.5 - 11.4) = 0.2 m

6 0
3 years ago
A weightlifter can exert an upward force of 3750 N. If a dumbbell has a mass of 225 kg, what is the maximum number of dumbbells
MrRissso [65]

Answer:

10 dumbbells

Explanation:

First we need to calculate the gravity on the moon.

0.166 x 9.8 m/s² = 1.627 m/s²  (the gravity is 0.166 times the Earth's gravity)

Taking this acceleration due to gravity, and multiplying it by the mass of a single dumbbell.

F = m x a

F = (225 kg) x (1.627 m/s²)

F = 366.075 N  (the amount of force exerted by the dumbbell)

Taking the weightlifter's total upward force and dividing it by the force exerted by one dumbbell, we can calculate the amount of dumbbells that can be carried.

(3750 N) / (366.075 N)

= 10.24 dumbbells  (but since there cannot be a fraction of a dumbbell, the answer is <u>10 dumbbells</u>).

6 0
3 years ago
Draw the graph of the cooling curve of Naphtalene; hence discuss the cooling curve of Nephtalene​
ioda

Answer:

soory but i cant under stand it proper can explain

5 0
3 years ago
Read 2 more answers
______ is/are usually the best conductor/s. a. Metals c. Air b. Water d. Minerals Please select the best answer from the choices
nataly862011 [7]
Metals are the best conductors.
8 0
3 years ago
Read 2 more answers
A 12.0 V car battery is being used to power the headlights of a car. Each of the two headlights has a power rating of 41.8 Watts
Marina CMI [18]

Answer:

n = 4.35 x 10¹⁹          

Explanation:

Given that

Voltage V= 12 V

Power rating of headlights = 41.8 W

We know that headlights of the car is connected in parallel connection.

We know that

Power = Current x Voltage

P = V I

I=\dfrac{41.8}{12}\ A

I=3.48  A

Therefore the total current will be

I'= 3.48 + 3.48 A

I = 6.96 A

We know that

Charge = Current x time

q= I' t

q= 6.96 x 1

q= 6.96 C

The charge on electron ,e= 1.6 x 10⁻¹⁹

q= n e

n=Number of electron

n=\dfrac{q}{e}

n=\dfrac{6.96}{1.6\times 10^{-19}}

n = 4.35 x 10¹⁹

5 0
3 years ago
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