Answer:
8.32 s⁻¹
Explanation:
Given that:
The concentration of myosin = 25 pmol/L
R_max = 208 pmol/L/s
The objective is to determine the turnover number of the enzyme molecule myosin, which has a single active site.
In a single active site of enzyme is known to be a region where there is binding of between substrate molecules, thereafter undergoing chemical reaction.
The turnover number of the enzyme is said to be the number of these substrate molecule which binds together are being converted into products.
The turnover number of the enzyme molecule of myosin can be calculated by the expression: 
⇒ 
= 8.32 s⁻¹
<span> quotation from "A Psalm of Life."
Let the dead past bury its dead!
</span><span> effect of the repetition of the word “dead” in this line is that </span>t reinforces the idea that one should live in the present, not in the past.
hope this helps
Answer:
7.3 mole
Explanation:
1 C6H10S gives 10H
0.73 mole of C6H10S gives X mole of Hydrogen
X= 0.73×10=7.3mole