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hodyreva [135]
3 years ago
5

Draw a highly magnified view of a sealed, rigid container filled with a gas. Then draw what it would look like if you cooled the

gas significantly but kept the temperature above the boiling point of the substance in the container. Also draw what it would look like if you heated the gas significantly. Finally, draw what each situation would look like if you evacuated enough of the gas to decrease the pressure by a factor of 2.

Chemistry
1 answer:
dusya [7]3 years ago
4 0

Answer:

In order to fully understand the issue of the ideal gas or perfect gas, we must pay attention to the following, an ideal or perfect gas does not really exist, it is a hypothetical gas whose sharing of the variables of pressure, volume and temperature can be fully described by the ideal gas equation.

The molecules that make up an ideal gas do not usually attract or repel each other, and their volume is negligible compared to the volume of the container that contains it. Although in our nature the case of an ideal gas does not exist, the differences between the behavior of a real gas in temperature and pressure margins do not substantially alter the calculations, so we can make use of the equation with all the security, to solve various gas exercises.

Explanation:

The collisions that occur between the molecules and with the molecules and with the walls is elastic because the moment is preserved, in addition to the kinetic energy.

It can be synthesized that a gas is ideal when all collisions that occur between atoms or molecules are completely elastic and there are no attractive forces that are intermolecular.

In ideal gases the kinetic energy is proportional to its temperature. The gases approach an ideal gas if they are mono atomic gases, if it is under pressure and also at room temperature.

The amount of gas in a body is measured in moles. One mole of any type of gas reaches 22.4 liters, in normal condition, 0 ° Celsius and 1 of the pressure atmosphere. That volume is called normal molar volume.

Ideal gases have an equation called the Ideal Gas Equation and is based on three main laws that are Boyle's law, Gay-Lussac's law, Charles's law and also Avogadro's law.

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Consider the following reaction where Kc = 1.80×10-2 at 698 K:2 HI (g) H2 (g) + I2 (g)A reaction mixture was found to contain 0.
Iteru [2.4K]

Answer:

Answer for the given statements: (1) T , (2) F , (3) T , (4) F , (5) F

Explanation:

At the given interval, concentration of HI = \frac{0.304}{1}M=0.304M

Concentration of H_{2} = \frac{5.07\times 10^{-2}}{1}M=5.07\times 10^{-2}M

Concentration of I_{2} = \frac{4.57\times 10^{-2}}{1}M=4.57\times 10^{-2}M

Reaction quotient,Q_{c} , for this reaction = \frac{[H_{2}][I_{2}]}{[HI]^{2}}

species inside third bracket represents concentrations at the given interval.

So, Q_{c}=\frac{(5.07\times 10^{-2})\times (4.57\times 10^{-2})}{(0.304)^{2}}=2.51\times 10^{-2}

So, the reaction is not at equilibrium.

As Q_{c}> K_{c} therefore reaction must run in reverse direction to reduce Q_{c} and make it equal to K_{c}. That means HI(g) must be produced and H_{2} must be consumed.

3 0
3 years ago
During a rainy spring, where are you most likely to find surface runoff
Dahasolnce [82]

Answer:On a sloped parking lot

Explanation:

7 0
3 years ago
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kicyunya [14]
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3 years ago
The acetylene tank contains 35.0 mol C2H2, and the oxygen tank contains 84.0 mol O2.
harkovskaia [24]

Answer:- As per the question is asked, 35.0 moles of acetylene gives 70 moles of carbon dioxide but if we solve the problem using the limiting reactant which is oxygen then 67.2 moles of carbon dioxide will form.

Solution:- The balanced equation for the combustion of acetylene is:

2C_2H_2(g)+5O_2(g)\rightarrow 4CO_2(g)+2H_2O(g)

From the balanced equation, two moles of acetylene gives four moles of carbon dioxide. Using dimensional analysis we could show the calculations for the formation of carbon dioxide by the combustion of 35.0 moles of acetylene.

35.0molC_2H_2(\frac{4molCO_2}{2molC_2H_2})

= 70molCO_2

The next part is, how we choose 35.0 moles of acetylene and not 84.0 moles of oxygen.

From balanced equation, there is 2:5 mol ratio between acetylene and oxygen. Let's calculate the moles of oxygen required to react completely with 35.0 moles of acetylene.

35.0molC_2H_2(\frac{5molO_2}{2molC_2H_2})

= 87.5molO_2

Calculations shows that 87.5 moles of oxygen are required to react completely with 35.0 moles of acetylene. Since only 84.0 moles of oxygen are available, the limiting reactant is oxygen, so 35.0 moles of acetylene will not react completely as it is excess reactant.

So, the theoretical yield should be calculated using 84.0 moles of oxygen as:

84.0molO_2(\frac{4molO_2}{5molO_2})

= 67.2molCO_2

7 0
4 years ago
Read 2 more answers
As a gas changes to a solid, energy<br> A. is not used.<br> B. is released.<br> C. is absorbed.
pogonyaev

Answer:

B

Explanation:

Energy is released, when a gas changes to solid

7 0
3 years ago
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