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3 years ago

Identify the type of reaction, write the products with phases, and balance. Show all work.

1 answer:

8 0

The correct classification of the reactions are as follows:

<span>1) 2Mg(s) + O2(g)----> 2MgO (s)
It is a synthesis reaction or a combination reaction. It involves the bonding of the reactant molecules forming one single molecule with new set of properties.

2) Na(s) + Cl2(g)------> NaCl(s)
It is a combination reaction as well, the same as the first reaction.

3). PbCO3(s)------> PbO(s)+Co2(g)
It is a decomposition reaction where a single molecule is breaks down into multiple molecules.

4). Ch4(g) + 2O2(g)----> CO2(g) + 2H2O(g)
It is a combustion reaction since it involves the reaction with oxygen and the production od carbon dioxide and water.</span>

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Calculate the molarity of (3.25 mol of LiCl in 2.78 L solution

alisha [4.7K]

$\text{Morality}= \dfrac{\text{Number of moles}}{\text{Volume}}=\dfrac{3.25}{2.78}=1.169 ~mol/L$

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2 years ago

During normal, relaxed respiration, about 500ml of air enters and leaves the lungs with each respiratory cycle. this is called t

Marianna [84]

During normal respiration, about 500ml of air enters and leaves the lungs with each respiratory cycle. This is called the<u> tidal volume</u>.

When a person is relaxed, the normal amount of air such a person breathes in and out is called the tidal volume. It is usually measured in millimeters. For the average adult male, it is 500ml, and the tidal volume of average adult female 400ml.

In order to regulate oxygen intake and expulsion of carbon dioxide, the lungs act as buffers in order to absorb the maximum amount of oxygen possible for respiration and other metabolic functions in the body.

When the tidal volume is above or below the 500ml mark, it could signal the presence of underlying pathological conditions like bronchitis, emphysema and asthma.

To find out more about tidal volume, visit:

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1 year ago

The primary anthropogenic source of atmospheric carbon dioxide (co2 ) is

Ket [755]

Burning of oil,gases and coal are the antropogenic source of co2

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3 years ago

An unknown compound, X is thought to have a carboxyl group with a pKa of 2.0 and another ionizable group with a pKa between 5 an

Westkost [7]

Answer:

7.3

Explanation:

By Henderson Hasselbalch equation we can calculate the pH or the pOH of a solution by its pKa. Remember that $pH = -log[H^{+}]$ , and pKa = -logKa. Ka is the equilibrium constant of the acid.

Henderson Hasselbalch equation :

$pH = pKa - log \frac{[HA]}{[A^{-}]}$

Where [HA] is the concentration of the acid, and $[A^{-}]$ is the concentration of the anion which forms the acid.

So, acid X, has two ionic forms, the carboxyl group and the other one. First, we have 0.1 mol/L of the acid, in 100 mL, so the number of moles of X

n1 = (0.1 mol/L)x(0.1 L) = 0.01 mol

When it dissociates, it forms 0.005 mol of the carboxyl group and 0.005 mol of the other group. Assuming same stoichiometry.

Adding NaOH, with 0.1 mol/L and 75 mL, the number of moles of $OH^-$ will be

n2 = (0.1 mol/L)x(0.075 L) = 0.0075 mol

So, the 0.0075 mol of $OH^-$ reacts with 0.005 mol of carboxyl, remaining 0.0025 mol of $OH^-$ , which will react with the 0.005 mol of the other group. So, it will remain 0.0025 mol of the other group.

The final volume of the solution will be 175 mL, but both concentrations (the acid form and ionic form) have the same volume, so we can use the number of mol in the equation.

Note that, the number of moles of the acid form is still 0.01 mol because it doesn't react!

So,

$6.72 = pKa - log \frac{0.01}{0.0025}$

6.72 = pKa - log 4

pKa - log4 = 6.72

pKa = 6.72 + log4

pKa = 6.72 + 0.6

pKa = 7.3

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3 years ago

The seeds of a dandelion are wispy and very light. A single dandelion produces many seeds. How does the structure of the seeds r

solmaris [256]

Answer:

the answer will be number...D

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3 years ago