Answer:Plant material, lignite, sub-bituminous, bituminous, and anthracite
Explanation: Decomposing plant material over time and under pressure forma lignite which is a very dirty type of coal. As time and pressure increase, more energy is released and the trend points that there are less pollutants when it is burned!
Answer:
Work done, W = 128 kJ
Explanation:
Given that,
Weight of a mountain climber, F = 800 N
It climbs to a cliff that is 160 m high.
We need to find the work done by the mountain climber. The work done by an object is given by the formula as follows :
W = Fd
Put the values of F and d.
W = 800 N × 160 m
W = 128000 J
or
W = 128 kJ
So, 128 kJ of work is done by the mountain climber.
Answer:
Solute concentration will afect the rate of a chemical reaction, because you must work with molarity
Explanation:
I think that solute mass may be it can affect the rate of reaction, if you have more mass in a solute, you will also have more moles.
If you want to know more, you have to consider temperature in the reaction and the presence of catalysts. They all, affect reactions.
Answer:
Here's what I get
Explanation:
The three resonance forms of N₂O are shown in the first diagram below (you can also use horizontal dashes to represent the bonding pairs).
To get the formal charge (FC) on the atoms, cut each bond in half, as in the second diagram.
Each atom gets the electrons on its side of the cut.
Formal charge = valence electrons in isolated atom - electrons on bonded atom
FC = VE - BE
(a) In Structure A
Left-hand N:
VE = 5
BE = 1 lone pair (2)+ 3 bonding electrons = 2 + 3 = 5
FC = 5 - 5 = 0.
Central N:
VE = 5
BE = 4
FC = 5 - 4 = +1
On O:
VE = 6
BE = 3 lone pairs(6) + 1 bonding electron = 7
FC = 5 - 6 = -1
(b) In Structure B
Left-hand N:
VE = 5
BE = 2 lone pairs (4)+ 2 bonding electrons = 4 + 2 = 6
FC = 5 - 6 = -1.
Central N:
VE = 5
BE = 4
FC = 5 - 4 = +1
On O:
VE = 6
BE = 2 lone pairs(4) + 2 bonding electrons = 6
FC = 6 - 6 = 0
(c) In Structure C
Left-hand N:
VE = 5
BE = 3 lone pairs (6)+ 1 bonding electrons = 6 + 1 = 7
FC = 5 - 7 = -2.
Central N:
VE = 5
BE = 4
FC = 5 - 4 = +1
On O:
VE = 6
BE = 1 lone pair(2) + 3 bonding electrons = 5
FC = 6 - 5 = +1