2NH3(g) = N2(g) + 3H2(g)
Before decomposed :
P NH3 = 2.7 atm
After decomposed :
P N2 = 0.54 atm
P H2 = P N2 / 3 = 0.54 / 3 = 0.18 atm
P NH3 = 2.7 - 2(0.18) = 2.34 atm
Pressure equilibrium constant :
Kp = (P N2)(P H2)³ / (P NH3)²
Kp = (0.54)(0.18)³ / (2.34)²
Kp = 5.75 × 10^(-4)
Answer:
454.3 g.
Explanation:
1.0 mol of CaO liberates → – 64.8 kJ.
??? mol of CaO liberates → - 525 kJ.
∴ The no. of moles needed = (1.0 mol)(- 525 kJ)/(- 64.8 kJ) = 8.1 mol.
<em>∴ The no. of grams of CaO needed = no. of moles x molar mass</em> = (8.1 mol)(56.077 g/mol) = <em>454.3 g.</em>
I'm not quite sure, but I believe that it would actually be "nuclear" because the sun would contain nuclear waves. And because of this, this would probably be the kind of reaction <span>the sun to release light and heat.</span>
Answer:
Explanation:
Cu(NO₃)₂ + 4NH₃ = Cu(NH₃)₄²⁺ + 2 NO₃⁻
187.5 gm 4M 1 M
187.5 gm reacts with 4 M ammonia
18.8 g reacts with .4 M ammonia
ammonia remaining left after reaction
= .8 M - .4 M = .4 M .
187.5 gm reacts with 4 M ammonia to form 1 M Cu(NH₃)₄²⁺
18.8 g reacts with .4 M ammonia to form 0.1 M Cu(NH₃)₄²⁺
At equilibrium , the concentration of Cu²⁺ will be zero .
concentration of ammonia will be .4 M
concentration of Cu(NH₃)₄²⁺ formed will be 0.1 M
Is this an addition problem?