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Oliga [24]
4 years ago
10

A saline solution contains 1.1% NaCl by mass. How much NaCl is present in 96.3 g of this solution

Chemistry
1 answer:
timurjin [86]4 years ago
8 0

Answer:

= 1.0593 g

Explanation:

1.1% NaCl by mass, means;

1.1 g per 100 g = 0.011

Therefore; the amount of NaCl present in 93.6 g of the solution is;

= 0.011 × 96.3 g

<u>= 1.0593 g</u>

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Explanation:

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- Using a catalyst

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The number of moles of Na_2SO_4 form from 5.0 moles Na_2S is 5 moles.

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Limiting reactants are those reactants that are completely used up in a chemical reaction.

4.0 mol Na_2S will be completely used since the combining ratio is 1 : 1 : 1.

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5 0
2 years ago
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STALIN [3.7K]

Answer:

Explanation:

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