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3 years ago

8

Wsp im fisdes once again hiiiii

2 answers:

xeze [42]3 years ago

7 0

Answer:

what?

Explanation:

⠀⠀⠀ ⠀⠀⣠⣤⣤⣤⣤⣤⣶⣦⣤⣄⡀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⢀⣴⣿⡿⠛⠉⠙⠛⠛⠛⠛⠻⢿⣿⣷⣤⡀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⣼⣿⠋⠀⠀⠀⠀⠀⠀⠀⢀⣀⣀⠈⢻⣿⣿⡄⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⣸⣿⡏⠀⠀⠀⣠⣶⣾⣿⣿⣿⠿⠿⠿⢿⣿⣿⣿⣄⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⣿⣿⠁⠀⠀⢰⣿⣿⣯⠁⠀⠀⠀⠀⠀⠀⠀⠈⠙⢿⣷⡄⠀ ⠀⠀⣀⣤⣴⣶⣶⣿⡟⠀⠀⠀⢸⣿⣿⣿⣆⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣿⣷⠀ ⠀⢰⣿⡟⠋⠉⣹⣿⡇⠀⠀⠀⠘⣿⣿⣿⣿⣷⣦⣤⣤⣤⣶⣶⣶⣶⣿⣿⣿⠀ ⠀⢸⣿⡇⠀⠀⣿⣿⡇⠀⠀⠀⠀⠹⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⡿⠃⠀ ⠀⣸⣿⡇⠀⠀⣿⣿⡇⠀⠀⠀⠀⠀⠉⠻⠿⣿⣿⣿⣿⡿⠿⠿⠛⢻⣿⡇⠀⠀ ⠀⠸⣿⣧⡀⠀⣿⣿⡇⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣿⣿⠃⠀⠀ ⠀⠀⠛⢿⣿⣿⣿⣿⣇⠀⠀⠀⠀⠀⣰⣿⣿⣷⣶⣶⣶⣶⠶⠀⢠⣿⣿⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⣿⣿⠀⠀⠀⠀⠀⣿⣿⡇⠀⣽⣿⡏⠁⠀⠀⢸⣿⡇⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⣿⣿⠀⠀⠀⠀⠀⣿⣿⡇⠀⢹⣿⡆⠀⠀⠀⣸⣿⠇⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⢿⣿⣦⣄⣀⣠⣴⣿⣿⠁⠀⠈⠻⣿⣿⣿⣿⡿⠏⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠈⠛⠻⠿⠿⠿⠿⠋⠁⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

Diano4ka-milaya [45]3 years ago

6 0

Answer:

heyyyyy

Explanation:

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Use the information for the isotopes of element X to calculate the average atomic mass of X, and identify the element. Isotope A

BigorU [14]

Answer

36.45 u; X = Cl

Explanation:

The atomic mass of X is the <em>weighted averag</em>e of the atomic masses of its isotopes.

We multiply the atomic mass of each isotope by a number representing its relative importance (i.e., its percent of the total).

Set up a table for easy calculation .

0.7577 × 34.969 u = 26.496 u

0.2423 × 36.965 u = <u> 8.9566 u </u>

TOTAL = 36.45 u

X = Cl

5 0

4 years ago

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What is the wavelength of an electron with a mass of 9.109×10−31 kg and a velocity of 3.43×107 ms? Use 6.626×10−34kg m2s for Pla

anyanavicka [17]

<u>Answer:</u> The wavelength of an electron is $2.121\times 10^{-11}m$

<u>Explanation:</u>

To calculate the wavelength of a particle, we use the equation given by De-Broglie's wavelength, which is:

$\lambda=\frac{h}{mv}$

where,

$\lambda$ = De-Broglie's wavelength = ?

h = Planck's constant = $6.626\times 10^{-34}Js$

m = mass of electron = $9.109\times 10^{-31}kg$

v = velocity of electron = $3.43\times 10^{7}m/s$

Putting values in above equation, we get:

$\lambda=\frac{6.626\times 10^{-34}Js}{(9.109\times 10^{-31}kg)\times (3.43\times 10^{7}m/s)}$

$\lambda=2.121\times 10^{-11}m$

Hence, the wavelength of an electron is $2.121\times 10^{-11}m$

6 0

4 years ago

The ---------- is directly above the troposphere

Debora [2.8K]

This would be the stratosphere. which is the second layer of the atmosphere.

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3 years ago

Atomic orbitals represent the wave functions that correspond to the solutions to the Schrödinger equation. The orbitals, which d

agasfer [191]

Explanation:

I'll give you a real answer later need points for test questions sorry

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3 years ago

Atoms are known to form charges due to their ability to gain and lose electrons in reactions. As a result, atoms become ions tha

Ivahew [28]

Answer:

C

Explanation:

Na has an electron configuration of 2,8,1

it forms an ion by losing 1 electron thus gaining a 1+ charge

5 0

3 years ago

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