Answer:
23.8 L
Explanation:
There is some info missing. I think this is the original question.
<em>Calculate the volume in liters of a 0.0380M potassium iodide solution that contains 150 g of potassium iodide. Be sure your answer has the correct number of significant digits.</em>
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The molar mass of potassium iodide is 166.00 g/mol. The moles corresponding to 150 grams are:
150 g × (1 mol/166.00 g) = 0.904 mol
0.904 moles of potassium iodide are contained in an unknown volume of a 0.0380 mol/L potassium iodide solution. The volume is:
0.904 mol × (1 L/0.0380 mol) = 23.8 L
One mole of methane has a mass of 16 g
When pH=7, [H⁺] =10⁻⁷.
When pH=5, [H⁺]=10⁻⁵.
10⁻⁵/10⁻⁷ =10²=100
The level of hydrogen ions increased by factor 100.
this equation does support the law of conservation of mass.
