1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nlexa [21]
3 years ago
5

fictitious element Jz has two common isotopes. Three-fifth of the isotopes have a mass of 329.1 amu, while the rest have a mass

of 334.5 amu. Given this information what is the average atomic mass (in amu) of Jz? Report the answer to 4 significant figures
Chemistry
1 answer:
Alla [95]3 years ago
7 0

The average atomic mass of Jz is 331.3 u.

The average atomic mass of Jz is the <em>weighted average</em> of the atomic masses of its isotopes.

We multiply the atomic mass of each isotope by a number representing its <em>relative importance</em> (i.e., its fractional abundance).  

Thus,

⅗ × 329.1 u = 197.46  u

⅖ × 334.5 u = <u>133.80 u</u>

      TOTAL = 331.3   u

You might be interested in
How many joules of heat are removed from a 21.0 g sample of water if it is cooled from 34.0°C
yaroslaw [1]

Answer:

527.184 J of heat is removed from a 21 g water sample if it is cooled from 34.0 ° C to 28.0 ° C.

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

When the heat added or removed from a substance causes a change in temperature in it, this heat is called sensible heat.

In other words, the sensible heat of a body is the amount of heat received or transferred by a body when it undergoes a change in temperature without there being a change in physical state (solid, liquid or gaseous). The equation that allows to calculate this heat exchange is:

Q = c * m * ΔT

Where Q is the heat exchanged by a body of mass m, constituted by a substance of specific heat c and where ΔT=Tfinal-Tinitial is the change in temperature.

In this case:

  • c= 4.184 \frac{J}{g*C}
  • m=21 g
  • ΔT=Tfinal-Tinitial=28 °C - 34 °C=-6 °C

Replacing:

Q= 4.184 \frac{J}{g*C} * 21 g* (-6 C)

Q= - 527.184 J

To lower the temperature, heat has to be given, for that the final temperature must be lower than the initial temperature; and it receives the name of transferred heat and has a negative value, as in this case.

<u><em> 527.184 J of heat is removed from a 21 g water sample if it is cooled from 34.0 ° C to 28.0 ° C.</em></u>

4 0
3 years ago
Which statement best describes a mole ?
pentagon [3]
<span>
It contains 6.02 mc001-1.jpg 1023 grams of sodium chloride.

It is the mass of 12 carbon atoms.

It contains 6.02 mc001-2.jpg 1023 particles of a given substance.</span>
5 0
3 years ago
Read 2 more answers
What is the definition of geosphere
Anton [14]
It's any of the almost spherical concentric regions of matter that make up the earth and it's atmosphere, as the lithosphere and hydrosphere. 
Hope this helps... If you could, could you mark my answer as brainliest? I'm trying to level lol 
5 0
3 years ago
Read 2 more answers
Various members of a class of compounds, alkenes, react with hydrogen to produce a corresponding alkane. Termed hydrogenation, t
Vitek1552 [10]

<u>Answer:</u> The mass of decane produced is 1.743\times 10^2g

<u>Explanation:</u>

To calculate the number of moles, we use the equation:  

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}       ......(1)

Mass of hydrogen gas = 2.45 g

Molar mass of hydrogen gas = 2 g/mol

Putting values in equation 1:, we get:

\text{Moles of }H_2=\frac{2.45g}{2g/mol}=1.225mol

The chemical equation for the hydrogenation of decene follows:

C_{10}H_{20}(l)+H_2(g)\rightarrow C_{10}H_{22}(s)

As, decene is present in excess. So, it is considered as an excess reagent.

Thus, hydrogen gas is a limiting reagent because it limits the formation of products.

By Stoichiometry of the reaction:

1 mole of hydrogen gas produces 1 mole of decane.

So, 1.225 moles of hydrogen gas will produce = \frac{1}{1}\times 1.225=1.225mol of decane

Now, calculating the mass of decane by using equation 1, we get:

Moles of decane = 1.225 mol

Molar mass of decane = 142.30 g/mol

Putting values in equation 1, we get:

1.225mol=\frac{\text{Mass of decane}}{142.30g/mol}\\\\\text{Mass of carbon dioxide}=(1.225mol\times 142.30g/mol)=174.3g=1.743\times 10^2g

Hence, the mass of decane produced is 1.743\times 10^2g

5 0
3 years ago
what tool do you have to use to precise amount of water? A meter stick B stopwatch C balance D graduated cylinder E beaker F the
Serhud [2]

Answer:

graduated cylinder

Explanation:

It shows exact volume very precisely.

8 0
3 years ago
Other questions:
  • Which process is spontaneous? electrolysis of water into oxygen and hydrogen spreading of a strong fragrance of perfume in a roo
    15·1 answer
  • Determine a planet from our solar system is located far from the sun. Describe the size and composition of this planet
    11·2 answers
  • Calculate the number of grams of carbon dioxide produced from 6 moles of oxygen gas. List only the number of grams of carbon dio
    15·1 answer
  • Student
    7·2 answers
  • What is the proper way to write sodium in crystal form
    15·1 answer
  • The spent fuel of a nuclear reactor contains plutonium-239, which has a half-life of 24,000 years. If 1 barrel containing 10 kg
    13·1 answer
  • A slide 3.3 m long makes an angle of 32° with the ground. How high is the top of the slide above the ground?
    6·1 answer
  • How many moles are in 11.0 grams of methane (CH4)?
    9·1 answer
  • Calculate the value of the equilibrium constant for the following system, where the concentrations of reactants and products are
    6·1 answer
  • Explain how movements along faults generate earthquakes<br><br><br>​
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!