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Zina [86]
3 years ago
6

Need help ASAP please show your work

Chemistry
1 answer:
VikaD [51]3 years ago
4 0

Answer:

q = 14049 J

Explanation:

q = m*c*(t2-t1)

q = 350 * 0.892 * (70-25) =

312.2 * 45 = 14049 J

I might be getting a little confused but I could be right.

Hope this helps!

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The correct mathematical expression for finding the molar solubility (s) of sn(oh)2 is:
lara [203]
Answer is: Ksp = 4s³.
Balanced chemical reaction (dissociation) of strontium hydroxide:
Sr(OH)₂(s) → Sr²⁺(aq) + 2OH⁻(aq).
Ksp(Sr(OH)₂) = [Sr²⁺]·[OH⁻]².<span>
[</span>Sr²⁺] = s.<span>
[</span>OH⁻] = [Sr²⁺] = 2s<span>
Ksp = (2s)² · x = 4s³.
Ksp is the solubility product constant for a solid substance dissolving in an aqueous solution.
[</span>Sr²⁺] is equilibrium concentration of iumcations.<span>
[</span>OH⁻] is equilibrium concentration of hydroxide anions.
7 0
3 years ago
What is the study of matter and it's changes.??
kupik [55]
<span>Physical Science is the study of matter and energy.
Physics is the study of matter, motion and energy.
Chemistry is the study of matter and its changes. Do you have an multiple choices?</span>
5 0
3 years ago
Tiny sacs in the lungs where gas exchange takes place are called ____?
SSSSS [86.1K]

Answer:

Alveoli

Explanation:

I hope this helps you.

8 0
3 years ago
Read 2 more answers
A sample of helium gas in a balloon is compressed from 4.0 L to 3.2 L at a constant temperature. If the pressure of the gas in t
vampirchik [111]

Answer:

286 kPa

Explanation:

Boyles law states that volume of gas is inversely proportional to pressure o gas for a fixed amount of gas at constant temperature

P1V1 = P2V2

where P1 is pressure and V1 is volume at first instance

P2 is pressure and V2 is volume at the second instance

substituting the values in the equation

229 kPa x 4.0 L = P2 x 3.2 L

P2 = 286.25 kPa

the new pressure is 286 kPa

4 0
3 years ago
A colorless liquid has a molar mass of 60.01 g/mol. When the liquid was analyzed, it was 46.7% nitrogen and 53.3% oxygen. What i
MAXImum [283]

first we have to find the empirical formula of the compound

empirical formula is the simplest ratio of whole numbers of components making up a compound

for 100 g of the compound

N O

mass 46.7 g 53.3 g

number of 46.7 g/ 14 g/mol 53.3 g/ 16 g/mol

moles = 3.34 mol = 3.33 mol

divide by the least number of moles

3.34/3.33 = 1.00 3.33/ 3,33 = 1.00

therefore number of atoms are

N - 1

O - 1

empirical formula is - NO


mass of empirical unit - 14 g/mol + 16 g/mol = 30 g

molecular formula is actual composition of elements in the compound

molecular mass - 60.01 g/mol


number of empirical units = molecular mass / empirical unit mass

= 60.01 g/mol / 30 g = 2

there are 2 empirical units


2(NO)

molecular formula = N₂O₂


6 0
3 years ago
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