Answer:
remain the same
Explanation:
The pH of the buffer system remain the same when 0.030 moles of strong acid are added because buffer system has the property to resist any change in the pH when acid or base is added to the solution. In buffer system, one molecule is responsible for neutralizing the pH of the solution by giving H+ or OH-.This molecule is known as buffer agent. If more base is added, the molecule provide H+ and when more acid is added to the solution, then the molecule add OH- to the solution.
Answer:
- <u>Decreasing the temperature of the system will shift the reaction rightward.</u>
Explanation:
The complete question is:
Given the equation representing a system at equilibrium:
- N₂(g) + 3H₂(g) ⇌ 2NH₃(g) + energy
what changes occur when the temperature of this system is decreased?
<h2>Solution</h2>
Modifying the temperature of a system in equilibrium changes the equilibrium constant and the equilibrium position (concentrations) of the system.
When the temperature is decreased, following LeChatelier's principle that the system will react in a way that seeks to counteract the disturbance, the reaction will shift toward the reaction that produces more heat energy to compensate the temperature decrease.
Thus, decreasing the temperature of the system will favor the forward reaction, more N₂(g) and H₂(g) will be consumed and more NH₃(g) and energy will be produced. Hence, the equilibrium will shift rightward.
3s it is what it says sorry if this is wrong but I just did a qu like this and that's what it was
Answer:
1.90 atm
Explanation:
Using ideal gas equation as:
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 0.0821 L atm/ K mol
According to above equation, at constant Volume and number of moles, pressure is directly proportional to the temperature. So,
Given ,
P₁ = 1.51 atm
P₂ = ?
T₁ = 23 °C
T₂ = 100 °C ( boiling point of water )
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (23 + 273.15) K = 296.15 K
T₂ = (100 + 273.15) K = 373.15 K
Using above equation as:
<u>New Pressure = 1.90 atm</u>
