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MA_775_DIABLO [31]
3 years ago
6

Which would have a higher boiling point, 1 mole of MgF, or 1 mole of Naci, if they are both dissolved in equal

Chemistry
1 answer:
Deffense [45]3 years ago
5 0

Answer:

MGF

Explanation:

Everyone knows NaCl is salt and that dissolves rather quickly without putting the temperature too high. Therefore MGF is the answer.

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The solubility product of PbI2 is 7.9x10^-9. What is the molar solubility of PbI2 in distilled water?
Agata [3.3K]

<u>Answer:</u> The molar solubility of PbI_2 is 1.25\times 10^{-3}mol/L

<u>Explanation:</u>

Solubility is defined as the maximum amount of solute that can be dissolved in a solvent at equilibrium.

Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.

The balanced equilibrium reaction for the ionization of calcium fluoride follows:

PbI_2\rightleftharpoons Pb^{2+}+2I^-

                s       2s

The expression for solubility constant for this reaction will be:

K_{sp}=[Pb^{2+}][I^-]^2

We are given:

K_{sp}=7.9\times 10^{-9}

Putting values in above equation, we get:

7.9\times 10^{-9}=(s)\times (2s)^2\\\\7.9\times 10^{-9}=4s^3\\\\s=1.25\times 10^{-3}mol/L

Hence, the molar solubility of PbI_2 is 1.25\times 10^{-3}mol/L

3 0
3 years ago
Will alka-seltzer fizz when added to apple juice?
Naddik [55]
Yes but only if you're talking about treated apple juice with a naturally small amount of water mixed in.
4 0
3 years ago
What type of mixture will not allow light to pass through
igor_vitrenko [27]
Suspension.  The particles are big enough for the eye to see, and will separate if left sitting.
5 0
3 years ago
If you had a glacier and an ice cube, how would the melting points of both differ?​
Dima020 [189]

Answer:

Due to how big the glacier is you would need more heat to melt it and since the ice cube is smaller a small amount of heat would melt it

Explanation:

8 0
3 years ago
What volume is occupied by 3.760 g of oxygen gas at a pressure of 88.4
Lorico [155]

Answer:

3.2 L

Explanation:

Given data:

Mass of oxygen = 3.760 g

Pressure of gas = 88.4 Kpa (88.4×1000 = 88400 Nm⁻²)

Temperature = 19°C (19+273.15 = 292.15 K)

R = 8.314 Nm K⁻¹ mol⁻¹

Volume occupied = ?

Solution:

Number of moles of oxygen:

Number of moles = mass/ molar mass

Number of moles = 3.760 g/ 32 g/mol

Number of moles = 0.12 mol

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant

T = temperature in kelvin

V = nRT/P

V = 0.12 mol ×  8.314 Nm K⁻¹ mol⁻¹ × 292.15 K /88400 Nm⁻²

V = 291.472 Nm /88400 Nm⁻²

V = 0.0032 m³

m³ to L:

V = 0.0032×1000 = 3.2 L

4 0
3 years ago
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