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Scilla [17]
2 years ago
13

How many moles are there in 17.5 grams of sodium? 22.99 1.05 × 1025 1.31 0.761 none of the above?

Chemistry
1 answer:
Alex_Xolod [135]2 years ago
6 0
 its B hopes this helps
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A patient needs 0.024 g of a sulfa drug. There are 12-mg tablets in stock. How many tablets should be given?
emmainna [20.7K]
I would personally convert the 12 mg to g so I could see what I was working with. So 12 mg to grams is 0.012 g...

so 1 tablet is 0.012g. the patient needs 0.024 g. 

so 0.024g/0.012g = 2 tablets or 0.012g X 2 is 0.024 g

hope this helps :)
7 0
3 years ago
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What does quantization refer to?
coldgirl [10]

Answer:

Having a specific set of possible values

6 0
1 year ago
Using the thermodynamic information in the ALEKS Data tab, calculate the standard reaction entropy of the following chemical rea
Aleksandr [31]

Answer:

ΔS° = - 47.2 J/mol.K

Explanation:

  • P4O10 + 6H2O → 4H3PO4

ΔS°= 4(S°mH3PO4) - 6(S°mH2O) - S°mP4O10

∴ S°mH2O(l) = 69.9 J/mol.K

∴ S°mP4O10 = 231 J/mol.K

∴ S°mH3PO4 = 150.8 J/mol.K

⇒ ΔS° = 4*(150.8) - 6*(69.9) - 231

⇒ ΔS° = - 47.2 J/mol.K

5 0
2 years ago
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how many moles of a nonvolatile, nonelectrolyte solute are required to lower the freezing point of 1000 grams of water by 5.58
Ivan

Answer:

Explanation:

Using freezing point depression formula,

ΔTemp.f = Kf * b * i

Where,

ΔTemp.f = temp.f(pure solvent) - temp.f(solution)

b = molality

i = van't Hoff factor

Kf = cryoscopic constant

= 1.86°C/m for water

= (0 - (-5.58))/1.86

= 3.00 mol/kg

Assume 1 kg of water(solvent)

= (3.00 x 1)

= 3.00 mol.

5 0
3 years ago
Measurements show that unknown compound X has the following composition: element mass % carbon 41.0% hydrogen 4.58% oxygen 54.6%
anastassius [24]

Answer:

CHO

Explanation:

Carbon = 41%,  Hydrogen = 4.58%, oxygen = 54.6%

Step 1:

Divide through by their respective relative atomic masses

41/ 12,         4.58/1,         54.6/16

3.41              4.58            3.41

Step 2:

Divide by the lowest ratio:

3.41/3.41,      4.58/3.41,     3.41/3.41

1,                    1,                  1

Hence the empirical formula is CHO

8 0
3 years ago
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