Y = 5x + 5
y - x = 5
You can use substitution to solve this system. Use y's expression (5x + 5) for y in the second equation to solve for x:
y - x = 5
5x + 5 + x = 5
6x + 5 = 5
6x = 0
x = 0
Substitute your value for x into one of the original equations to y:
y = 5x + 5
y = 5(0) + 5
y = 5
Finally, substitute both values into both original equations to check your work:
5 = 5(0) + 5 --> 5 = 5 <--True
5 - 0 = 5 --> 5 = 5 <--True
Answer:
x = 0
y = 5
Answer:
after what.................. ???
Answer:
y=7x + 5
Step-by-step explanation:
sub into y= mx + c
where m = slope/gradient (7)
and c = y-value of y-intercept (5)
Answer:
1. 7/10, 2. 25, 3. 1/4 4. 4. 3/5, 5. A
Step-by-step explanation:
1. Make a fraction with the total number of cards at the bottom (60) and all the cards that are not green (aka yellow and blue) on top (42). Then simplify the fraction 42/60 by dividing both terms by 6 to get 7/10
2. For this one, first find how many students out of the first 80 liked basketball by subtracting the 60 students who liked other sports from 80. This gives you 20. Now you know that 20/80 students like basketball. Now simplify the fraction to get 1/4. Then find 1/4 of 100, because we know that 1/4 of students like basketball. 1/4 of 100 is 25.
3. This problem is exactly the same as number 1, except instead of adding all the other colors and putting them as a fraction over the total, just put the number of pink shirts over the total number of shirts to get 3/12. Then simplify it to 1/4, and that's your answer.
4. This is also similar to problems 1 and 3. Just put the number of heads coin tosses over the total and simplify it.
5. This one is very similar to all the problems so far. I will let you do this one on your own. Remember: The number of cases (rolls or colors or sports or cards etc.) that you want to find the probability for goes on top, and the total number of those things goes on the bottom. The bigger the fraction, the greater probability there is.
Note: Please only ask one question at a time on here instead of 5 at once. Since these problems are so similar, chances are, you could have figured them out on your own with a little help on one of them. You are more likely to get a quick answer if the answerer doesn't have to do as much work.
