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ch4aika [34]
3 years ago
5

Can someone please help me with the with this

Chemistry
1 answer:
solong [7]3 years ago
4 0

Answer:

Chemical

Explanation:

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Which of the following is an example of a mixture?
kap26 [50]
B. the atmosphere is an example of a mixture
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3 years ago
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Calculate the pOH and the pH of a 5.0 x 10-2 M solution of NaOH.
k0ka [10]

Answer:

pOH = 1.3, pH = 12.7

Explanation:

Since NaOH is a strong base, it will completely ionize; further, since it completely ionizes, our hydroxide concentration (a product of the ionization) will be the same as the given concentration of NaOH.

NaOH -> Na⁺ + OH⁻, [OH⁻] = 5.0 x 10^-2 M

pOH is the negative log of the hydroxide concentration, so plug our hydroxide concentration in:

pOH = -log[OH⁻] = -log[5.0 x 10^-2 M] = 1.3

Since pH + pOH = 14, we can plug in pOH and solve for pH:

pH + 1.3 = 14

pH = 14 - 1.3 = 12.7

Thus, our pOH = 1.3 and pH = 12.7.

5 0
3 years ago
Question 5
Dafna11 [192]

The mass percent of oxygen is 32.82%.

<h3>What is a noble gas?</h3>

A noble gas is member of group 18 in the periodic table. The members of this group are known not to be reactive and they do not easily form compounds. However, there have been few compounds of the members of group 18 that have been reported.

Let us now calculate the relative molecular mass of xenon tetraoxide.

Xe + 4 (O)

131 + 4(16) = 195

Given that the mass of oxygen in the compound is 64, the mass  percent of oxygen in xenon tetroxide is obtained from;

64/195 * 100/1

= 32.82%

Learn more about mass percent:brainly.com/question/5394922

#SPJ1

5 0
1 year ago
A fixed quantity of gas fills a volume of 10.6 liters at 638 torr and 83 C. Find the volume it will occupy if the pressure is 10
sukhopar [10]
According to this formula:
(P1V1) / T1 = (P2V2) / T2

convert T from C° to Kelvin:
T1 = 83 + 273 = 356 K
T2= 96 + 273 = 369 K

convert P from torr to atm:
1 torr = 0.00131578947 atm<span>
p1 = 0.839474 atm
P2 = 1.415789 atm
By substitution in the previous formula:
(0.839474 x 10.6 ) / (356) = ( 1.415789 x V2 ) / 369
So:
V2 = 6.5 L</span>
5 0
3 years ago
Calculate the mass of water formed when 4g of methane is burnt in excess oxygen​
wariber [46]

Answer:

Mass of water formed: 9g

Explanation:

Hope it helps you!

6 0
3 years ago
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