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2 years ago

10

HELPPPPPPPPPPP???????

1 answer:

svetoff [14.1K]2 years ago

7 0

Answer:

new moon

when the moon is front of the sun its a new moon

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Why is aluminium used to make outer covering of aeroplane?

iogann1982 [59]

Answer:

Aluminum is ideal for aircraft manufacture because it's lightweight and strong. Aluminum is roughly a third the weight of steel, allowing an aircraft to carry more weight and or become more fuel efficient. Furthermore, aluminum's high resistance to corrosion ensures the safety of the aircraft and its passengers.

Explanation:

8 0

2 years ago

Do electric or magnetic fields affect the x-rays?

Levart [38]

Electric and magnetic fields do not affect xrays as they only affect charged particles and xrays have no charge

hope that helps

3 0

2 years ago

Hexane and octane are mixed to form a 45 mol% hexane solution at 25 deg C. The densities of hexane and octane are 0.655 g/cm3 an

avanturin [10]

Answer:

The required volume of hexane is 0.66245 Liters.

Explanation:

Volume of octane = v=1.0 L= $1000 cm^3$

Density of octane= d = $0.703 g/cm^3$

Mass of octane ,m= $d\times v=0.703 g/cm^3\times 1000 cm^3=703 g$

Moles of octane = $\frac{m}{114 g/mol}=\frac{703 g}{114 g/mol}=6.166 mol$

Mole percentage of Hexane = 45%

Mole percentage of octane = 100% - 45% = 55%

$55\%=\frac{6.166 mol}{\text{Total moles}}\times 100$

Total moles = 11.212 mol

Moles of hexane :

$45%=\frac{\text{moles of hexane }}{\text{Total moles}}\times 100$

Moles of hexane = 5.0454 mol

Mass of 5.0454 moles of hexane,M = 5.0454 mol × 86 g/mol=433.9044 g

Density of the hexane,D = $0.655 g/cm^3$

Volume of hexane = V

$V=\frac{M}{D}=\frac{433.9044 g}{0.655 g/cm^3}=662.4494 cm^3\approx 0.66245 L$

(1 cm^3= 0.001 L)

The required volume of hexane is 0.66245 Liters.

5 0

3 years ago

Which of the following options correctly ranks solid iodine, liquid bromine, and chlorine gas in order of increasing intermolecu

tatuchka [14]

Answer:

solid iodine chlorine gas

7 0

3 years ago

1. How many moles of CO2 can be produced from a reaction of 10.0 moles CzHg?

mr_godi [17]

Answer:

$20$ moles of CO2 can be produced from a reaction of 10.0 moles C2H6

Explanation:

In this reaction -

2 moles of C₂H6 produces four molecules of Carbon dioxide (CO2)

So 1 mole of C₂H6 will produce $\frac{4}{2} = 2$ moles of Carbon dioxide (CO2)

Thus, 10 moles of C₂H6 will produce $2 * 10 = 20$ moles of Carbon dioxide (CO2)

3 0

2 years ago