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algol13
2 years ago
5

What could you change or add to your models based on what you have learned about molecules and phases so far?

Chemistry
2 answers:
timurjin [86]2 years ago
5 0

Answer:Phase changes require either the addition of heat energy (melting, evaporation, and sublimation) or subtraction of heat energy (condensation and freezing). ... Changing the amount of heat energy usually causes a temperature change.

Explanation:

babymother [125]2 years ago
3 0
Ummm I don’t know ‍♀️
You might be interested in
Please help
inna [77]

From the calculation, the standard free energy of the system is -359kJ.

<h3>What is the standard free-energy?</h3>

The  standard free-energy is the energy present in the system. We have to first obtain the cell potential using the formula;

Ereduction - E oxidation = 0.96 V - 0.34 V = 0.62 V

Using the formula;

ΔG = -nFEcell

ΔG =-(6 * 96500 * 0.62)

ΔG =-359kJ

Learn more about free energy:brainly.com/question/15319033

#SPJ1

3 0
2 years ago
How much heat must your body transfer to 500.0g of water to heat it from 25.0°C to body temperature, 37.0°C?
shtirl [24]

Answer : The heat your body transfer must be, 25.1 kJ

Explanation :

Formula used :

Q=m\times c\times \Delta T

or,

Q=m\times c\times (T_2-T_1)

where,

Q = heat = ?

m = mass of water = 500.0 g

c = specific heat of water = 4.18J/g^oC

T_1 = initial temperature  = 25.0^oC

T_2 = final temperature  = 37.0^oC

Now put all the given value in the above formula, we get:

Q=500.0g\times 4.18J/g^oC\times (37.0-25.0)K

Q=25080J=25.1kJ

Therefore, the heat your body transfer must be, 25.1 kJ

3 0
3 years ago
Balance this equation <br><br>Fe2O2 + C -&gt; Fe + CO2​
lidiya [134]

2 FeO + 1 C ===》2 Fe + 1 CO2

8 0
3 years ago
Read 2 more answers
How many atoms does 2.0 moles of He represent
Rudiy27

We use the following formula to calculate the number of atoms:

n (mol) = N(number of atoms) / NA

N(He) = n(mol) · NA

N(He) = 2,0 moles · 6.02·1023 = 12.04·1023 atoms

6 0
3 years ago
The theoretical yield of a reaction is the amount of product obtained if the limiting reactant is completely converted to produc
Elis [28]

Answer: 9.9 grams

Explanation:

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

a) moles of H_2

\text{Number of moles}=\frac{8.150g}{2g/mol}=4.08moles

b) moles of C_2H_4

\text{Number of moles}=\frac{9.330g}{28g/mol}=0.33moles

H_2(g)+C_2H_4(g)\rightarrow C_2H_6(g)

According to stoichiometry :

1 mole of C_2H_4 combine with 1 mole of H_2

Thus 0.33 mole of C_2H_4 will combine with =\frac{1}{1}\times 0.33=0.33 mole of H_2

Thus C_2H_4 is the limiting reagent as it limits the formation of product.

As 1 mole of C_2H_4 give =  1 mole of C_2H_6

Thus 0.33 moles of C_2H_4 give =\frac{1}{1}\times 0.33=0.33moles  of C_2H_6

Mass of C_2H_6=moles\times {\text {Molar mass}}=0.33moles\times 30g/mol=9.9g

Thus theoretical yield (g) of C_2H_6 produced by the reaction is 9.9 grams

7 0
3 years ago
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