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3 years ago

A large prime number isP = 232582657 - 1

Engineering

1 answer:

sattari [20]3 years ago

3 0

Answer:

32582657

Explanation:

If any number is in the form of 2^{n}-1 is known as Mersenne prime. Here, n is a prime number.

For example:

If n is 3 then the corresponding binary number is as follows:

P=2^{3}-1

P=7

Here, the binary representation of P is (111)₂.

The number of binary digits is 3 which are equal to n.

Consider the given expression

P=2^32582657-1

This is also in the form 2^{n}-1

Here the value of n is 32582657.

Hence, the number of binary digits for the given prime number is 32582657

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Explain why it is important to understand hydrostatic forces on surfaces when designing scuba gear, particularly oxygen tanks, f

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Answer:

Explained

Explanation:

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3 years ago

How did the Ecole des Beaux Arts contribute to the development of the architect role into a profession?

Aneli [31]

Answer:

B. The Ecole, for the first time anywhere in the world, provided a formalized course of study for becoming an architect

Explanation:

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3 years ago

A 35 ft simply supported beam is loaded with concentrated loads 15 ft in from each support. On one end, the dead load is 8 kips

agasfer [191]

Answer: ASD = 306 kips-ft

LRSD = 1387.5 k-ft

Explanation:

To begin, we will take a step by step process to solving this problem.

Attached below is a picture to guide us to solving this.

To begin, we have that to reaction of the support

ΣMд = 0

where;

RB * 35 - (8+18)15 - (4+9)20 = 0

RB = 18.57k

also Ey = 0;

RA + RB = 18 + 8 + 9 +4 = 20.43 k

taking the maximum moment at mid point;

Mc = RA * 35/2 - (8 +18) (35/2 -15)

Mc = 292.525

therefore, MD = RA * 15 = 20.43 * 15 = 306.45 k.ft

MD = 306.45 k.ft

ME = 279 k.ft i.e 18.57 * 15

considering the unsupported length; 35 - (15*2 = 5ft

now we have that;

Lb = Lp = 5ft

where Lp = 1.76 ry(√e/fy)

Lp = 1.76 ry √29000/50 ......

ry = 1.4 inch

so we have that Mr = Mp for Lb = Lp where

Mp = 2 Fy ≤ 1.5 sx Fy

Recall from the expression,

RA + RB = (8+4) * 1.2 + (18+9) * 1.6 = 57.6

RA * 35 = 4 * 1.2 * 15 + 9 *1.6 * 15 + 8 * 1.2 * 20 + 18 * 1.6 * 20

RA = 30.17 k

the maximum moment at D = 30.17 * 15 = 452.55 k.ft

Zrequired = MD/Fy = 452.55 * 12 / 50 = 108.61 inch³

so we have Sx = 452.55 * 12 / 1.5 * 50 = 72.4 inch³

also r = 1.41 in

Taking LRFD solution:

where the design strength ∅Mn = 0.9 * Zx * Fy

given r = 2.97

Zx = 370 and Sx = 81.5, we have

∅Mn = 0.9 * 370 * 50 = 16650 k-inch = 1387.5 k-ft

this tells us it is safe.

ASD solution:

for Lb = Lp, and where Mn = Mp = Fcr Sx

we already have value for Sx as 81.5 so

Fcr = ZxFy/Sx

Fcr = 370 * 50 / 81.5 = 227 ksi

considering the strength;

Strength = Mn / Ωb = (0.6 * 81.5 * 50) * (1.5) / 12 = 306 kips-ft

This justifies that it is safe because is less than 306

cheers i hope this helps.

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3 years ago

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MrMuchimi

Answer:

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ArrayList [var-name] = new ArrayList<data-type>()

From the question;

We understand that the variable name is: a

And the data-type is: Thing

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ArrayList a = new ArrayList<Thing>();

Hence:

None of the options answers the question.

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Explanation:

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