Answer: drugs and rushing cars
Explanation: drug dealers are everywhere on city streets nowadays they have been killing young adults
rushing cars or reckless drivers cut curb fast and potentially someone can get hurt they are speeding and not worrying about other people lives at stake
Answer:
See attached images for the diagrams and tables
Elastic Potential Energy is zero detailed description is given below.
Explanation:
- It is the energy stored in stretched or compressed elastic materials. This also means that elastic potential energy is zero in objects that have not been stretched or compressed.
- To determine the gravitational potential energy of an object, a zero height position must first be arbitrarily assigned. Typically, the ground is considered to be a position of zero height. But this is merely an arbitrarily assigned position that most people agree upon. Since many of our labs are done on tabletops, it is often customary to assign the tabletop to be the zero height position. Again this is merely arbitrary. If the tabletop is the zero position, then the potential energy of an object is based upon its height relative to the tabletop. For example, a pendulum bob swinging to and from above the tabletop has a potential energy that can be measured based on its height above the tabletop. By measuring the mass of the bob and the height of the bob above the tabletop, the potential energy of the bob can be determined.
- Potential energy is the energy that is stored in an object due to its position relative to some zero position. An object possesses gravitational potential energy if it is positioned at a height above (or below) the zero height. An object possesses elastic potential energy if it is at a position on an elastic medium other than the equilibrium position.
Since the gravitational potential energy of an object is directly proportional to its height above the zero position, a doubling of the height will result in a doubling of the gravitational potential energy. A tripling of the height will result in a tripling of the gravitational potential energy.
Answer:
W = 1 mJ
V_new = 2000 V
W_new = 2 mJ
The extra energy came from the work done from moving the plates
Explanation:
We are given;
Capacitance; C = 1000pF = 10^(-9) F
Voltage; V = 1000V
Now,formula for stored energy in a parallel plate capacitor is given by;
W = (1/2)CV² = (1/2)(10^(-9))(1000²) = 0.5 mJ
However, in this case, it's W = 0.5 x 2 = 1 mJ since parallel-plate capacitor with air dielectric
When plates are moved and distance between plates is doubled(net charge is the same), thus we can calculate voltage from;
Q = CV
Since, C_new = C/2
Thus,
Q = (C/2)V_new
V_new = 2Q/C
Thus, V_new = 2V
Thus, V_new = 2 x 1000 = 2000 V
Now,
W_new = (1/2)C_new•(V_new)² = (1/2) (0.5C)•(2V)² = CV² = 2W = 2 x 1 = 2mJ
