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docker41 [41]
3 years ago
15

All peopleid 5603642259 pd 123456on z o o m​

Engineering
1 answer:
algol [13]3 years ago
3 0

Hello,

What is the ID Zoom for?

Like what in particular???

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What is the weight density of a 2.24 in diameter titanium sphere that weights 0.82 lb?
nasty-shy [4]

Answer:

0.14\ lb/in^{3}

Explanation:

Density is defined as mass ler unit volume, expressed as

\rho=\frac {m}{v}

Where m is mass, \rho is density and v is the volume. For a sphere, volume is given as

v=\frac {4\pi r^{3}}{3}

Replacing this into the formula of density then

\rho=\frac {m}{\frac {4\pi r^{3}}{3}}

Given diameter of 2.24 in then the radius is 1.12 in. Substituting 0.82 lb for m then

\rho=\frac {0.82}{\frac {4\pi 1.12^{3}}{3}}=0.13932044952427\approx 0.14 lb/in^{3}

4 0
3 years ago
Who here is a genius?
Pachacha [2.7K]

Answer:

im kinda smart  whyy?

Explanation:

3 0
3 years ago
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Can some help me with this !!! Is 26 points!!
Aleonysh [2.5K]
Third one
15,000,000 ohms because M=10^6
8 0
3 years ago
What are the conditions for sheet generator to build up its voltage?
MA_775_DIABLO [31]

Answer:

There are six conditions

1. Poles should contain some residual flux.

2. Field and armature winding must be correctly connected so that initial mmm adds residual flux.

3. Resistance of field winding must be less than critical resistance.

4. Speed of prime mover of generator must be above critical speed.

5. Generator must be on load.

6. Brushes must have proper contact with commutators.

Explanation:

3 0
3 years ago
A residential heat pump has a coefficient of performance of 1.49 How much heating effect, in kJ/h, will result when 4 kW is supp
AfilCa [17]

Answer:

21.456 kJ/h

Explanation:

See the figure attached. In this case  

W_{cycle} = 4 kW

Q_{out} = \text{heating effect}

Coefficient of performance in heat pump is defined by

COP = \frac{Q_{out}}{W_{cycle}}

Q_{out} =COP*W_{cycle}

Q_{out} =1.49*4 \, W

Q_{out} = 5.96 \, W

Now it is necessary to change units, remember that Watt (W) is defined as J/s

Q_{out} = 5.96 \frac{J}{s} \frac{3600s}{1 h} \frac{1 kJ}{1000 J}

Q_{out} = 21.456 \frac{kJ}{h}

3 0
3 years ago
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