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Mekhanik [1.2K]
3 years ago
8

HELP!!

Mathematics
1 answer:
Setler [38]3 years ago
4 0
23.  If M' represents the complementary, then is the answer A.

24.  The answer is C.


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The pyramid shown has a square base that is 32 centimeters on each side. The slant height is 24 centimeters. What is the lateral
masya89 [10]
L.S.A.=1/2pl where p represents the perimeter of the base and l the slant height.
L.S.A. = ½(4*32)(24)
L.S.A. = ½ (128)(24)
L.S.A. =1/2(3072)
L.S.A. = 1536 cm
6 0
3 years ago
Read 2 more answers
Sheesh i need help… first to get it right earns the brainliest !!
Olin [163]

Answer:

They are congruent, they are right angles

Step-by-step explanation:

Just in general, all vertical angles are congruent.

But in this situation, perpendicular lines will always create right angles.

4 0
2 years ago
25 points + brainly please answer quick
TiliK225 [7]

Answer:

use the pythagoras theorem

Step-by-step explanation:

4^{2} = 2^2 + (2\sqrt{3})^2\\  16 = 4 + 12\\16 = 16\\hence they are the sides of right angled triangle

6 0
3 years ago
Read 2 more answers
P(t) = 250 * (3.04)^t/1.98,
Alex17521 [72]

Answer:

The concept which best describes the change of the population is the derivative of p(t)=250(3.04)^{\frac{t}{1.98}}.

Step-by-step explanation:

Observe that the function p(t)=250(3.04)^{\frac{t}{1.98}} describes the amount of rabbits at the time t (in years) but  no the rate of change of the population at a given instant. So you have to use the derivative of p(t) to obtain that rate of change at any instant. For example, if we derivate the function p(t)=250(3.04)^{\frac{t}{1.98}} we obtain:

p'(t)=250\cdot \log(\frac{1}{1.98})(3.04)^{\frac{t}{1.98}}

And if we want to find the rate of change at t=5 years we evaluate

p'(5)=250\cdot \log(\frac{1}{1.98})(3.04)^{\frac{5}{1.98}}=2326 rabbits/year

5 0
3 years ago
When the outliers are removed, how does the mean change? dot plot with 1 on 50, 1 on 76, 1 on 78, 2 on 79, 1 on 80, 1 on 81, 2 o
sveticcg [70]
We can plot this data on MS Excel and determine the distribution of these data reflected on the graph. Among these numbers, 50 is the outlier since it is very far from the other numbers ranging from 76 to 83. We can perform interquartile range to determine or verify the outliers in the data set. In this respect, we can see that there is not much distribution seen. The average of all data sets is equal to 96.25. When the outlier (50) is removed, we expect the mean to become higher since a low number was ommitted including high numbers only. Outliers are obtained from special causations such as human errors. 

5 0
2 years ago
Read 2 more answers
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