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Alinara [238K]
3 years ago
13

A rubber ball is filmed as it bounces on a sidewalk at 25 frames every second. Predict how many seconds of film will be shown in

1,750 frames.
Please help!!!!! And could you explain I don't get this AT ALL!!!!
Mathematics
1 answer:
ANEK [815]3 years ago
8 0
If for one second we have to reserve 25 frames to find length of the movie we have to divide 1750 by 25, so
1750:25=70 [seconds] - its the result

To better understand lets think that u have 8 piece of cake and u want to give every person 2 piece. To find how many person u can invite u can divide 8 by 2. The answer is 4 here ofc.
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Factor completly x^2 -64
Hoochie [10]

∑ Hey, jillianwagler ⊃

Answer:

\left(x+8\right)\left(x-8\right)

Step-by-step explanation:

<u><em>⇒ Given info:</em></u>

<em>Factor completely </em>x^2 -64

<u><em>⇒ Solution:</em></u>

<em>Rewrite 64 as 8 ² because 8² is equal to 64. 8 ² = 8 × 8 = 64.</em>

<em />=x^2-8^2

Applying difference of two squares formula: x^2-y^2=\left(x+y\right)\left(x-y\right)

=x^2-8^2=\left(x+8\right)\left(x-8\right)\\

=\left(x+8\right)\left(x-8\right)

Answer~: \left(x+8\right)\left(x-8\right)

<u><em>xcookiex12</em></u>

<em>8/19/2022</em>

7 0
2 years ago
For many years businesses have struggled with the rising cost of health care. But recently, the increases have slowed due to les
kaheart [24]

Answer:

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=1.96

The margin of error for this case is given by:

ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

And replacing we got:

ME = 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.0259

And replacing into the confidence interval formula we got:

0.52 - 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.4941

0.52 + 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.5459

And the 95% confidence interval would be given (0.4941;0.5459).

Step-by-step explanation:

Data given and notation  

n=1000 represent the random sample taken    

\hat p=0.52 estimated proportion of of U.S. employers were likely to require higher employee contributions for health care coverage

\alpha=0.05 represent the significance level (no given, but is assumed)    

Solution to the problem

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=1.96

The margin of error for this case is given by:

ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

And replacing we got:

ME = 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.0259

And replacing into the confidence interval formula we got:

0.52 - 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.4941

0.52 + 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.5459

And the 95% confidence interval would be given (0.4941;0.5459).

5 0
3 years ago
Which of the following is a monomial???
aleksandrvk [35]
Monomial is a product of numbers and variables in any whole power.
Examples of monomials: 5, y, 2x, 2x⁷, 2xyz, 6x²y¹⁰⁰.
Monomial cannot have log,subtraction or addition, negative power.
x/y=xy⁻¹

So, only monomial here is A.y
7 0
3 years ago
Column vector (4, 1) has been rotated to column vector (-1, 4). Which matrix carried out the transformation?
OLEGan [10]

Answer:

C.(3|-4)

Step-by-step explanation:

5 0
3 years ago
1 unit by 2 units by<br> units
Julli [10]

Answer:

2

Step-by-step explanation:

1 unit by 2 unit means area.

So, know that in area you multiply length times width, you multiply 2 and 1.

1·2

Which is 2

8 0
3 years ago
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