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Sav [38]
3 years ago
12

Question: How does the total amount of energy present before an energy transformation compare to the total amount of energy pres

ent afterward?
A: The energy before is equal to the energy afterward.

B: The mass before is equal to the mass afterward.

C: The energy before is greater than the energy afterward.

D: The energy afterward is greater than the energy before.
Physics
2 answers:
sasho [114]3 years ago
7 0

Answer: A

Explanation: i took the test

juin [17]3 years ago
5 0
The correct option is: (A) <span>The energy before is equal to the energy afterward.

Explanation:
According to the law of conservation of Energy, energy can neither be created nor destroyed; it can only be transformed into one form or another. It means that the total initial energy must be equal to the total final energy of the system. By considering this law, we can infer that the energy before is equal to the energy afterward.</span>
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A 150 g baseball is traveling horizontally at 50 m/s. If the ball takes 20 ms to stop once it is in contact with the catcher’s g
Sliva [168]
To solve for force, you need to get the product of mass and acceleration. 
F = ma

Your given is:
m = 150g
a = ?
v = 50 m/s
t = 20ms

As you can see, you do not have acceleration yet. But if you read the problem you can come up with the formula of acceleration. 
Acceleration is the change in velocity over a period of time.

a = change in velocity/time

To get the change in velocity, you get the difference between the initial velocity and final velocity:

a =  \frac{vf-vi}{t}

The ball was moving initially at a velocity of 50 m/s and it came to a stop. This is your clue. If a ball comes to a stop then that means that the final velocity of the ball is 0 m/s. 

So we can put it into our formula now:

a = \frac{0m/s-50m/s}{20ms}

WAIT! As you can see, the units do not match. We have ms and s into our equation and that means you cannot proceed till they are the same. First we need to convert ms to s. 

20ms x \frac{1s}{1000ms} = \frac{20s}{1000} = 0.02s

So your new time is 0.02s. Now we put this time into the formula:


a = \frac{0m/s-50m/s}{0.02s}
a =  \frac{-50m/s}{0.02s}  = -2,500 m/ s^{2}

As you can see our acceleration is a negative value, this indicates that it decelerated or slowed down which makes sense because it was brought to a stop. 

So now we have our acceleration. Now using this, we can get our force. 

F= ma

Before we start doing this, you need to take note that the unit of force is N, but when you expand it, it is kg.m/ s^{2} but as you can see our mass given is in grams. So again, before you put them into the equation we need to change it into kg first. 

150g =  \frac{1kg}{1,000g}  =  \frac{150kg}{1,000}  = 0.150kg

Our new mass is 0.150kg. 

To make things clearer, let us write down all our new values:

m = 0.150kg
a = -2,500 m/ s^{2}

Now that all our units match, we can put that into our formula:

F= ma
F= (0.150kg)(-2,500m/s^{2})
F = -375kg.m/ s^{2}  or -375N

The value again is negative because it is going against the initial direction of the ball. But if your instructor just wants to get the value of force or the magnitude of the force, just disregard the sign. 



4 0
4 years ago
What is the equivalent resistance between terminals A and B, measured in ohms?
Usimov [2.4K]

Answer:

c. 0.80

Explanation:

they will choose the path that has not resistance

8 0
3 years ago
The pressure of a gas is reduced from 1200.0 mm hg to 850.0 mm hg as the volume of its container is increased by moving a piston
Kamila [148]
From gas laws:
\frac{PV}{T} = Constant

Therefore,
\frac{ P_{1}  V_{1} }{ T_{1} } =  \frac{ P_{2}  V_{2} }{ T_{2} }

P1 = 1200 mm
V1 = 85 ml
T1 = 90°C = 363.15 K
P2 = 850 mm
V2 = 350 ml
T2 = ?

Substituting;
T_{2} =  \frac{ P_{2}  V_{2}  T_{1} }{ P^{1}  V^{1} } =  \frac{850*350*363.15}{1200*85} = 1059.19 K = 786.04 °C
8 0
4 years ago
Read 2 more answers
A car speeds up from 18.54 m/s to<br> 29.52 m/s in 13.84 s.<br> The acceleration of the car is:
valkas [14]

Answer:

.7934m/s^{2}

Explanation:

Acceleration = change in velocity / change in time

A = 10.98m/s / 13.84s

A = .7934m/s^{2}

5 0
3 years ago
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Your mass in kilograms if you weight 170 pounds
Aleonysh [2.5K]
1 pound ≈ 0.4536 kg

170 pounds ≈ 170 * 0.4536 kg

                     ≈ 77.112 kg

                      
5 0
3 years ago
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