1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sav [38]
3 years ago
12

Question: How does the total amount of energy present before an energy transformation compare to the total amount of energy pres

ent afterward?
A: The energy before is equal to the energy afterward.

B: The mass before is equal to the mass afterward.

C: The energy before is greater than the energy afterward.

D: The energy afterward is greater than the energy before.
Physics
2 answers:
sasho [114]3 years ago
7 0

Answer: A

Explanation: i took the test

juin [17]3 years ago
5 0
The correct option is: (A) <span>The energy before is equal to the energy afterward.

Explanation:
According to the law of conservation of Energy, energy can neither be created nor destroyed; it can only be transformed into one form or another. It means that the total initial energy must be equal to the total final energy of the system. By considering this law, we can infer that the energy before is equal to the energy afterward.</span>
You might be interested in
Alpha particles, each having a charge of +2e and a mass of 6.64 ×10-27 kg, are accelerated in a uniform 0.50 T magnetic field to
sergij07 [2.7K]

Answer:

KE=1.2036\times 10^{-12}\ J

Explanation:

Given:

  • charge on the alpha particle, q=2e=3.2\times 10^{-19}\ C
  • mass of the alpha particle, m=6.64\times 10^{-27}\ kg
  • strength of a uniform magnetic field, B=0.5\ T
  • radius of the final orbit, r=0.5\ m

<u>During the motion of a charge the magnetic force and the centripetal forces are balanced:</u>

q.v.B=m.\frac{v^2}{r}

m.v=q.B.r

where:

v = velocity of the alpha particle

v=\frac{q.B.r}{m}

v=\frac{3.2\times 10^{-19}\times 0.5\times 0.5}{6.64\times 10^{-27}}

v=1.2048\times 10^{7}\ m.s^{-1}

Here we observe that the velocity of the aprticle is close to the velocity of light. So the kinetic energy will be relativistic.

<u>We firstly find the relativistic mass as:</u>

m'=\frac{1}{\sqrt{1-\frac{v^2}{c^2} } } \times m

m'=\frac{6.64\times 10^{-27}}{\sqrt{1-\frac{(1.2048\times 10^7)^2}{(3\times 10^8)^2} } }

m'=6.6533\times10^{-27}\ kg

now kinetic energy:

KE=m'.c-m.c

KE=6.6533\times 10^{-27}\times (3\times 10^8)^2-6.64\times 10^{-27}\times (3\times 10^8)^2

KE=1.2036\times 10^{-12}\ J

6 0
3 years ago
What are three examples of constructive forces
Olin [163]
The three main constructive forces are crustal deformation, volcanic eruptions, and deposition of sediment.
5 0
2 years ago
The sensor in the torso of a crash test dummy records the magnitude and direction of the net force acting on the dummy.If the du
Sunny_sXe [5.5K]

Here in crash test the two forces are acting on the dummy in two different directions

As we know that force is a vector quantity so we need to use vector addition laws in order to find the resultant force on it.

So here two forces are given in perpendicular direction with each other so as per vector addition law we need to use Pythagoras theorem to find the resultant of two vectors

so we can say

F_{net} = \sqrt{F_1^2 + F_2^2}

here given that

F_1 = 130.0 N

F_2 = 4500.0 N

now we will plug in all data in the above equation

F_{net} = \sqrt{4500^2 + 130^}

F_{net} = 4501.9 N

so it will have net force 4501.9 N which will be reported by sensor

4 0
2 years ago
Read 2 more answers
A 388 Hz tuning fork is resonating in a closed tube on a warm day when the speed of sound is 346 m/s. What is the length of the
Marizza181 [45]

Answer:

A

Explanation:

because u are subtracting if this is from flvs that is what i did and it was right

5 0
3 years ago
Read 2 more answers
An airplane engine starts from rest; and 2 seconds later, it is rotating with an angular speed of 300 rev/min. if the angular ac
elena-s [515]

First of all, we need to convert the angular speed from rev/min into rev/s:

\omega_f=300 rev/min=5 rev/s

The angular acceleration is the variation of angular speed divided by the time:

\alpha=\frac{\omega_f-\omega_i}{t}=\frac{5 rev/s-0}{2 s}=2.5 rev/s^2

And this is constant, so we can use the following equation to calculate the angle through which the engine has rotated:

\theta(t)=\frac{1}{2}\alpha t^2 =\frac{1}{2}(2.5 rev/s^2)(2 s)^2=5 rev

so, 5 revolutions.

3 0
2 years ago
Other questions:
  • When you spill a few drops of soup or milk on a pale-blue Gas game when cooking, the color of the flame changes to a mixture of
    14·1 answer
  • ASAP PLEASE HELPPP
    8·1 answer
  • Which is larger, 65mph or 120kph? As a percentage, how much faster is one than the other?
    5·2 answers
  • Calculate the gravitational potential energy a 1kg ball has when thrown 3 m into the air. The gravitational field strength on ea
    10·1 answer
  • If v lies in the first quadrant and makes an angle Ï/3 with the positive x-axis and |v| = 4, find v in component form.
    5·1 answer
  • A ray of yellow light ( f8= 5.09 × 1014 Hz) travels at a speed of 2.04×10 meters per second in
    6·2 answers
  • Which subatomic particle will you add or remove from an atom to create a new element?
    5·1 answer
  • )) What do these two changes have in common?
    8·1 answer
  • Can someone help me with this question please picture is above
    15·1 answer
  • Is a neutron positive ornegative
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!