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3 years ago

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What is the chemical formula for mercury(I) nitrate? Hgmc021-1.jpg(NOmc021-2.jpg) Hg(NOmc021-3.jpg)mc021-4.jpg Hgmc021-5.jpg(NOm

c021-6.jpg)mc021-7.jpg Hgmc021-8.jpg(NOmc021-9.jpg)mc021-10.jpg

2 answers:

Anit [1.1K]3 years ago

8 0

If you just type "<span>What is the chemical formula for mercury(I) nitrate?" into google you get the answer but HG(NO3)2 is the correct one.
sorry no one helped you in time hope you passed anyway</span>

Anton [14]3 years ago

3 0

Answer: The symbol of Mercury(I) nitrate: $HgNO_3$

Explanation:

Symbol of the mercury metal is Hg.
The symbol of nitrate ion is $NO_3^-$ .

The chemical formula of Mercury(I) nitrate: $HgNO_3$

It is formed by the combination of mercury ion and nitrate ion. Nitrate ion is a polyatomic ion.

The reaction for the combination of the ions to form mercury (I) nitrate follows the equation:

$Hg^++NO_{3}^-\rightarrow HgNO_3$

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A circuit contains two resistors in series. The voltage drop across the first is 10 V. The voltage drop across the second is als

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Hi there!

Voltage in a series can be expressed by the following:

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In words, the total voltage is equal to the sum of the individual voltage drops in a SERIES circuit.

We can solve for the total voltage:

$V_T = 10 + 10 = \boxed{\text{ D. 20 V}}$

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1 year ago

A low orbit satellite at 100 km altitude had a camera that resolved a car location to within 0.3 meter. Find the minimum diamete

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Answer:

Minimum diameter of the camera lens is 22.4 cm

The focal length of the camera's lens is 300cm

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y = Resolve distance = 0.3 m

h = Height of satellite = 100 km

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$sin\theta=1.22\frac{\lambda}{D}\\\Rightarrow D=1.22\frac{\lambda}{sin\theta}\\\Rightarrow D=1.22\frac{550\times 10^{-9}}{sin3\times 10^{-6}}=0.2236\ m=22.4\ cm$

Minimum diameter of the camera lens is 22.4 cm

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3 years ago

Kevin goes bowling. Whenever he bowls the ball, he transfers energy from his hand to the bowling ball. The amount of energy befo

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Answer:the answer is C

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2 years ago

What are the physical and chemical properties of sodium?

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Answer:

Physical Properties of Sodium

Atomic number 11

Melting point 97.82°C (208.1°F)

Boiling point 881.4°C (1618°F)

Volume increase on melting 2.70%

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Lenntech Water treatment & purification

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Home Periodic table Elements Sodium

Sodium - Na

Chemical properties of sodium - Health effects of sodium - Environmental effects of sodium

Atomic number

11

Atomic mass

22.98977 g.mol -1

Electronegativity according to Pauling

0.9

Density

0.97 g.cm -3 at 20 °C

Melting point

97.5 °C

Boiling point

883 °C

Vanderwaals radius

0.196 nm

Ionic radius

0.095 (+1) nm

Isotopes

3

Electronic shell

[Ne] 3s1

Energy of first ionisation

495.7 kJ.mol -1

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2 years ago

A heat engine accepts 200,000 Btu of heat from a source at 1500 R and rejects 100,000 Btu of heat to a sink at 600 R. Calculate

diamong [38]

To solve the problem it is necessary to apply the concepts related to the conservation of energy through the heat transferred and the work done, as well as through the calculation of entropy due to heat and temperatra.

By definition we know that the change in entropy is given by

$\Delta S = \frac{Q}{T}$

Where,

Q = Heat transfer

T = Temperature

On the other hand we know that by conserving energy the work done in a system is equal to the change in heat transferred, that is

$W = Q_{source}-Q_{sink}$

According to the data given we have to,

$Q_{source} = 200000Btu$

$T_{source} = 1500R$

$Q_{sink} = 100000Btu$

$T_{sink} = 600R$

PART A) The total change in entropy, would be given by the changes that exist in the source and sink, that is

$\Delta S_{sink} = \frac{Q_{sink}}{T_{sink}}$

$\Delta S_{sink} = \frac{100000}{600}$

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On the other hand,

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$\Delta S_{source} = \frac{-200000}{1500}$

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$S = 33.34Btu/R$

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PART B)

Work done by heat engine is given by

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