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vodka [1.7K]
3 years ago
11

What is the chemical formula for mercury(I) nitrate? Hgmc021-1.jpg(NOmc021-2.jpg) Hg(NOmc021-3.jpg)mc021-4.jpg Hgmc021-5.jpg(NOm

c021-6.jpg)mc021-7.jpg Hgmc021-8.jpg(NOmc021-9.jpg)mc021-10.jpg
Physics
2 answers:
Anit [1.1K]3 years ago
8 0
If you just type "<span>What is the chemical formula for mercury(I) nitrate?" into google you get the answer but HG(NO3)2 is the correct one.
sorry no one helped you in time hope you passed anyway</span>
Anton [14]3 years ago
3 0

Answer: The symbol of Mercury(I) nitrate: HgNO_3

Explanation:

  • Symbol of the mercury metal is Hg.
  • The symbol of nitrate ion is NO_3^-.

The chemical formula of Mercury(I) nitrate: HgNO_3

It is formed by the combination of mercury ion and nitrate ion. Nitrate ion is a polyatomic ion.

The reaction for the combination of the ions to form mercury (I) nitrate follows the equation:

Hg^++NO_{3}^-\rightarrow HgNO_3

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Answer:

Explanation:

Let the potential difference between the middle point and one of the plate be ΔV .

electric potential energy will be lost and it will be converted into kinetic energy .

Electrical potential energy lost = Vq , where q is charge on charge particle .

For proton

ΔV× q = 1/2 M V² ( kinetic energy of proton )

where M is mass and V be final velocity of proton .

For electron

ΔV× q = 1/2 m v² ( kinetic energy of electron  )

where m is mass and v be final velocity of electron . Charges on proton and electron are same in magnitude .

As LHS of both the equation are same , RHS will also be same . That means the kinetic energy of both proton and electron will be same

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In other words , their velocities  are  inversely proportional to square root of their masses .

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3 years ago
A .5 kg air puck moves to the right at 3 m/s, colliding with a 1.5kg air puck that is moving to the left at 1.5 m/s.
Bas_tet [7]

Answer:

Explanation:

Total momentum of the system before the collision

.5 x 3 - 1.5 x 1.5 = -0.75 kg m/s towards the left

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Applying conservation of momentum

2 v = -  .75

v =  - .375 m /s

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2 ) To verify whether the collision is elastic or not , we verify whether the kinetic energy is conserved or not.

Kinetic energy before the collision

= 2.25 + 1.6875

=3.9375 J

kinetic energy after the collision

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So kinetic energy is not conserved . Hence collision is not elastic.

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1.5 - (-1.0965 )

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3 years ago
7. Starting at rest, a car accelerates at 5.5m/s/s for 12s. What is its
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Answer:

66 m/s

Explanation:

v=u+at

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3 years ago
Why are there temperature differences on the moon's surface even though there is no atmosphere present?
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The lack of an atmosphere means convection cannot happen on the moon. Therefore, there is no form of heat dissipation on regions in direct sunlight. In addition, the lack of an atmosphere means there is no greenhouse effect on the moon. This is why regions facing away from sunlight are very cold.  

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This is a conservation of momentum question. You have an object initially at rest (cart) so that object is initially at 0 momentum. Indiana Jones is 83.5 kg and running 3.75 m/s so he starts with a momentum of 313.125 kg * m/s because momentum is equal to mass * velocity. Once the person jumps in the cart, the cart and the person can be considered one object and by conservation of momentum, the momentum of the Indiana-cart system is equal to 313.125 kg * m/s. By that, we can set that momentum equal to the combined mass * joint velocity. So 313.125 = (83.5kg + 312kg) * joint velocity. Then just solve for the velocity. The answer should be smaller than the intial velocity of the person of 3.75 m/s because the mine cart is HUGE at 312kg.

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3 years ago
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