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victus00 [196]
3 years ago
8

A motor is used to operate a lift. There is a man in the lift. The input power of the motor is 6200 watts. The lift and the man

have a total mass of 580 kg. The lift moves up a distance of 12 m in 15 s. Calculate the tension in the cable when the lift is moving at constant speed.
Physics
1 answer:
Assoli18 [71]3 years ago
8 0

Answer: 8500 N

Explanation:

You are given that the input power of the motor is 6200 watts

Since the man is in the lift, and the lift and the man have a total mass of 580 kg. The power 6200 watt is responsible to move up the lift and the man. Where power is the rate at which work is done. That is

Power = workdone/ time

But workdone = force × distance

Substitute that in power formula

Power = force × distance/time

But distance/time = velocity

Therefore, power is the product of force and velocity. That is,

P = FV

If the lift moves up a distance of 12 m in 15 s, then,

Velocity V = 12/15 = 0.8 m/s

Substitutes V and P into the power formula

6200 = F × 0.8

F = 6200/0.8

F = 8500 N

The calculated force is equal to the tension in the cable when the lift is moving at a constant speed.

Therefore, the tension in the cable is equal to 8500 N

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Explanation:

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3 years ago
2. The components of vector A are given as follows:
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50 degree.

Explanation:

Given that the components of vector A are given as follows: Ax = 5.6 Ay = -4.7

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Substitute Ay and Ax into the formula above.

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3 years ago
A particle executes simple harmonic motion with an amplitude of 2.18 cm.
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Speed v at any displacement y is given by  

v^{2} = w^{2} (A^{2} - y^{2})   ........................................................  i

And,

               v = \frac{1}{2} v (max)  

          or,  2 × v = Aω     ....................................................   ii

Eliminating  ω from equations i and ii,

                       \frac{1}{4} A^{2}  w^{2}  =  w^{2}  ( A^{2}  - y^{2})

                     or, y^{2} =  (\frac{3}{4}) A^{2}  =(\frac{3}{4}) 2.18^{2}

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3 0
3 years ago
A 60.00-cm guitar string under a tension of 50.000 N has a mass per unit length of 0.100 00 g/cm chegg
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Fundamental frequency,

f=v2l=T/μ−−−−√2l

=(50)/0.1×10−3/10−22×0.6−−−−−−−−−−−−−−−−−−−√

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Let, n th harmonic is the hightest frequency, then

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∴N=339.38

Hence, 339 is the highest frequency.

∴fmax=(339)(58.93)Hz=19977Hz.

<h3>What is frequency?</h3>

In physics, frequency is the number of waves that pass a given point in a unit of time as well as the number of cycles or vibrations that a body in periodic motion experiences in a unit of time. After moving through a sequence of situations or locations and then returning to its initial position, a body in periodic motion is said to have experienced one cycle or one vibration. See also simple harmonic motion and angular velocity.

learn more about frequency refer:

brainly.com/question/254161

#SPJ4

7 0
2 years ago
A ferry coming into port is sailing at 12 m/s. It takes 2.5km to come to rest in the port. Calculate the deceleration of the fer
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For the position equation of the ferry we need to integrate again over time:

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p(  (12m/s)/A) = 2500m =  (-A/2)*( (12m/s)/A)^2 + (12m/s)*((12m/s)/A)

2500m = (-72 m^2/s^2)/A + (144m^2/s^2)/A

2500m = (72 m^2/s^2)/A

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A = (72 m^2/s^2)/2500m = 0.0288 m/s^2

and the acceleration of the ferry was -A, then the acceleration of the ferry is:

-0.0288 m/s^2

4 0
3 years ago
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