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sweet [91]
4 years ago
5

A rocket is continuously firing its engines as it accelerates away from Earth. For the first kilometer of its ascent, the mass o

f fuel ejected is small compared to the mass of the rocket. For this distance, which of the following indicates the changes, if any, in the kinetic energy of the rocket, the gravitational potential energy of the Earth-rocket system, and the mechanical energy of the Earth-rocket system? System Gravitational System Potential Energy Rocket Kinetic Energy Mechanical Energy
(A) Increasing IncreasingIncreasing
(B) Increasing Increasing Constant IncreasingDecreasing Decreasing Decreasing Increasing Constant
Physics
1 answer:
melisa1 [442]4 years ago
3 0

Answer:

A) Increasing,  Increasing,  Increasing

Explanation:

The greater the rate of fuel ejection higher will be the kinetic energy of the rocket. As rocket is fire upward its fuel rejection rate increases and hence it's kinetic energy increases.

Gravitational potential energy,

as the rocket moves further it's r from the Earth increases. Hence the Gravitational potential energy increases as its height from the Earth increases.

Therefore,  mechanical energy of the rocket must also increase as it is sum of kinetic and potential energy.

Hence Option A is correct.

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A 20 kg truck drives in a circle of radius 4 m at 10m/s. What is the centripetal acceleration of the truck?
asambeis [7]

Answer:

B. 25 m/s/s

Explanation:

Centripetal acceleration is the square of the tangential velocity divided by the radius of curvature.

a = v² / r

Given v = 10 m/s and r = 4 m:

a = (10 m/s)² / 4 m

a = 25 m/s²

4 0
3 years ago
Problem 3: A basketball player is running at 4.75 m/s toward the basket when he jumps into the air to dunk the ball. He maintain
LekaFEV [45]

Answer

given,

speed of the basketball player, v_x = 4.75 m/s

height of the jump = ?

a) initial vertical velocity = 0 m/s

   final vertical velocity = ?

       height, h = 0.75 m

 using equation of motion

   v² = u² +  2 g h

   v² = 0² +  2 x 9.8 x  0.75

   v² = 14.7

   v = 3.83 m/s

b) let horizontal distance= x m

 maximum height at time , t s

 time taken to reach maximum height

    t = \dfrac{3.83}{9.8}

         t = 0.39 s

    horizontal distance

             = v_x  × t

             = 4.75 × 0.39

             = 1.85 m

horizontal distance is equal to 1.85 m

8 0
3 years ago
If the loading is 0.4, the coinsurance rate is 0.2, the number of units of medical care is 100, and the number of units of medic
s344n2d4d5 [400]

Answer:

72  is the premimum of the insurance.

Explanation:

Below is the given values:

The loading = 0.4

Coinsurance rate = 0.2

Number of units = 100

Total number of units = 100 * 0.4 = 40

Remaining units = 60 * 0.2 = 12

Add the 60 and 12 values = 60 + 12 = 72

Thus, 72  is the premimum of the insurance.

8 0
3 years ago
Pls help me this is being timed. pls.
ahrayia [7]

Answer:

10N each

Explanation:

Doing a little math here to make it balanced. 10+10=20 therefore you have the same on both sides.

Hope this helps!

6 0
3 years ago
Jessica stretches her arms out 0.60 m from the center of her body while holding a 2.0 kg mass in each hand. She then spins aroun
Juliette [100K]

Answer:

a.) L = 2.64 kgm^2/s

b.) V = 4.4 m/s

Explanation: Jessica stretches her arms out 0.60 m from the center of her body. This will be considered as radius.

So,

Radius r = 0.6 m

Mass M = 2 kg

Velocity V = 1.1 m/s

Angular momentum L can be expressed as;

L = MVr

Substitute all the parameters into the formula

L = 2 × 1.1 × 0.6 = 1.32kgm^2s^-1

the combined angular momentum of the masses will be 2 × 1.32 = 2.64 kgm^2s-1

b. If she pulls her arms into 0.15 m,

New radius = 0.15 m

Using the same formula again

L = 2( MVr)

2.64 = 2( 2 × V × 0.15 )

1.32 = 0.3 V

V = 1.32/0.3

V = 4.4 m/s

Her new linear speed will be 4.4 m/s

4 0
3 years ago
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