Answer:
Force between two charges is given as 1.296 N
Explanation:
As we know that the two charges will attract or repel each other when they are placed near to each other
Here we know that electrostatic force is given as

here we have

distance between two charges is given as
r = 0.50 m
so we have


Use the formular d = v x t
d = 2m
v= 100m/s
t= d / v
= 2 / 100
= 0.02sec
Answer:
Doubled
Explanation:
F = (kq1q2) / r^2
F and q (Either q1 or q2) are directly proportional, so double the charge would also double the electruc force between the charges.
1. Velocity at which the packet reaches the ground: 121.2 m/s
The motion of the packet is a uniformly accelerated motion, with constant acceleration
directed downward, initial vertical position
, and initial vertical velocity
. We can use the following SUVAT equation to find the final velocity of the packet after travelling for d=750 m:

substituting, we find

2. height at which the packet has half this velocity: 562.6 m
We need to find the heigth at which the packet has a velocity of

In order to do that, we use again the same SUVAT equation substituting
with this value, so that we find the new distance d that the packet travelled from the helicopter to reach this velocity:

Which means that the heigth of the packet was
