All categories

3 years ago

What does overloading your muscles accomplish?

Physics

2 answers:

Vadim26 [7]3 years ago

7 0

Answer:

Explanation:

You are putting more strain on your muscles which is ripping the fibers which will grow back bigger.

Serga [27]3 years ago

4 0

Answer:

The correct option is A

Explanation:

Overloading of muscle is caused by subjecting the muscle to more stress than they are accustomed to. This is the technique used by body builders to build the muscle mass. When the muscle is continuously subjected to this added stress, it eventually adapts to this stress by producing new myofibrils (which makes up the muscle fibre). This added stress causes the muscle fibre to grow bigger and stronger in order to handle this additional stress subsequently.

You might be interested in

Your friend, who is in a field 100 meters away from you, kicks a ball towards you with an initial velocity of 16 m/s. Assuming t

LekaFEV [45]

Answer:

Time, t = 5.355 seconds

Explanation:

Given the following data;

Distance = 100 m

Initial velocity = 16 m/s

Deceleration = 1 m/s²

To find the time, we would use the second equation of motion;

But since the ball is decelerating, it's acceleration would be negative.

S = ut + ½at²

Where;

S represents the displacement or height measured in meters.

u represents the initial velocity measured in meters per seconds.

t represents the time measured in seconds.

a represents acceleration measured in meters per seconds square.

Substituting into the equation, we have;

100 = 16t - 0.5t²

200 = 32t - t²

t² + 32t - 200 = 0

Solving the quadratic equation using the quadratic formula;

The quadratic equation formula is;

$x = \frac {-b \; \pm \sqrt {b^{2} - 4ac}}{2a}$

Substituting into the equation, we have;

$x = \frac {-32 \; \pm \sqrt {32^{2} - 4*1*(-200)}}{2*1}$

$x = \frac {-32\pm \sqrt {1024 - (-800)}}{2}$

$x = \frac {-32 \pm \sqrt {1024 + 800}}{2}$

$x = \frac {-32 \pm \sqrt {1824}}{2}$

$x = \frac {-32 \pm 42.71}{2}$

$x_{1} = \frac {-32 + 42.71}{2}$

$x_{1} = \frac {10.71}{2}$

x1 = 5.355

We do not need the negative value of x, so we proceed.

Therefore, time = 5.355 seconds

3 0

3 years ago

Question: Point B is 25 km due east of point A. Starting from point A, a camel walks 20 km in

Korolek [52]

<em>Resultant angle; θ = 25.59° </em>

This question is dealing with bearings and distance.

We are told that from point A, the camel walks 20 km at 15° in the south of east direction.

Thus, d_s,e = 20 km

Resolving along the horizontal east direction gives; d_e = 20 cos 15

d_e = 19.32 km

Also, resolving along the vertical south direction gives; d_s = 20 sin 15

d_s = 5.18 km

Net vertical distance; d_vert = 8km - 5.18km = 2.72 km

Net horizontal distance; d_hor = 25km - 19.32 km = 5.68 km

Now, the resultant angle is given by;

tan θ = d_vert/d_hor

tan θ = 2.72/5.68

tan θ = 0.4789

θ = tan^(-1) 0.4789

θ = 25.59°

Read more at; brainly.com/question/22518031

8 0

3 years ago

A railroad car having a mass of 15 Mg is coasting at 1.5 m/s on a horizontal track. At the same time another car having a mass o

luda_lava [24]

Answer:

Explanation:

We shall apply law of conservation of momentum to know velocity after collision . Let it be v .

total momentum before collision = total momentum after collision

15 x 1.5 - 12 x .75 = ( 15 + 12 ) v

v = .5 m /s

kinetic energy before collision

1/2 x 15 x 1.5² + 1/2 x 12 x .75²

= 16.875 + 3.375

= 20.25 J

kinetic energy after collision

= 1/2 x ( 15 + 12 ) x .5²

= 3.375 J

Loss of energy = 16.875 J

This energy appear as heat and sound energy that is produced during collision .

4 0

3 years ago

What is the total amount of kinetic and potential energy in a system ?

Solnce55 [7]

Answer:

Its the sum of the potential energy and the kinetic energy

7 0

3 years ago

Find the resultant of two components, 3km west and 4 km south. How do I solve this using the Pythagorean theorem?

Rasek [7]

Answer:5

Explanation:

a=3

b=4

c=√(a²+b²)

c=√9+16

c=√25

c=5

3 0

3 years ago