Answer:
10v / 7
Explanation:
Using the conservation law of momentum
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
m v - 0.7 m v₁ = ( 0.7 m + m) 0 m/s since the cart stuck together after collision. taken right to be positive and left to be negative
m v - 0.7 m v₁ = 0
- 0.7 m v₁ = -m v
v₁ = -m v / - 0.7 m = 10v / 7
50 hertz hope this helps :)
Answer:
2.35 m/s²
Explanation:
Given that
Mass of the smaller crate, m₁ = 21 kg
Mass of the larger crate, m₂ = 90 kg
Tensión of the rope, T = 261 N
We know that the sum of all forces for the two objects with a force of friction F and a tension T are:
(i) m₁a₁ = F
(ii) m₂a₂ = T - F, where m and a are the masses and accelerations respectively.
1) no sliding can also mean that:
a₁ = a₂ = a
This makes us merge the two equations written above together as:
m₂a = T - m₁a
If we then solve for a, we would have something like this
a = T / (m₁+m₂)
a = 261 / (21 + 90)
a = 261 / 111
a = 2.35 m/s²
Therefore, the needed acceleration of the small crate is 2.35 m/s²
