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Vesnalui [34]
3 years ago
14

Unpolarized light with an intensity of 22.4 ????ux passes through a polarizer whose transmission axis is vertically oriented. (a

) What is the direction of the polarized beam and intensity of the transmitted light? (b) If the polarizer’s transmission axis is at an angle of 69.0° with the vertical, what is the intensity of the transmitted light and its direction? (9 pts)
Physics
1 answer:
irina1246 [14]3 years ago
8 0

Answer:

a)      I₁ = 11.2 Lux , vertical direction , b)      I₂ = 1.44 Lux

Explanation:

a) A polarized is a system that absorbs light that is not polarized in the direction of its axis, therefore half of the non-polarized light must be absorbed

consequently the above the processed light has half of the incident intensity and the directional of the polarized

          I₁ = I₀ / 2

          I₁ = 22.4 / 2

          I₁ = 11.2 Lux

is polarized in the vertical direction

b) The polarized light falls on a second polarizer, therefore it must comply with the law of Malus

         I₂ = I₁ cos² θ

         I₂ = 11.2 cos² 69

         I₂ = 1.44 Lux

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<h3>What is Speed?</h3>

Speed is simply referred to as distance traveled per unit time.

Mathematically, Speed = Distance ÷ time.

Given the data in the question;

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We substitute our given values into the expression above.

Speed = Distance ÷ time

1.08 × 10⁹km/h = 4.0 × 10¹³km ÷ t

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Answer:

r=5.278\times 10^{-4}\ m

Explanation:

Given that:

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<em>Now, form the mathematical expression of Kinetic Energy:</em>

KE= \frac{1}{2} m.v^2

1.92\times 10^{-19}=0.5\times 9.1\times 10^{-31}\times v^2

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r=\frac{m.v}{q.B}

r=\frac{9.1\times 10^{-31}\times 6.496\times 10^6 }{1.6\times 10^{-19}\times 0.07}

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<u>We are Given:</u>

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