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3 years ago

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Unpolarized light with an intensity of 22.4 ????ux passes through a polarizer whose transmission axis is vertically oriented. (a

) What is the direction of the polarized beam and intensity of the transmitted light? (b) If the polarizer’s transmission axis is at an angle of 69.0° with the vertical, what is the intensity of the transmitted light and its direction? (9 pts)

1 answer:

irina1246 [14]3 years ago

8 0

Answer:

a) I₁ = 11.2 Lux , vertical direction , b) I₂ = 1.44 Lux

Explanation:

a) A polarized is a system that absorbs light that is not polarized in the direction of its axis, therefore half of the non-polarized light must be absorbed

consequently the above the processed light has half of the incident intensity and the directional of the polarized

I₁ = I₀ / 2

I₁ = 22.4 / 2

I₁ = 11.2 Lux

is polarized in the vertical direction

b) The polarized light falls on a second polarizer, therefore it must comply with the law of Malus

I₂ = I₁ cos² θ

I₂ = 11.2 cos² 69

I₂ = 1.44 Lux

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Answer:

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Explanation:

From the question we are told that

Mass of pitcher $M= 2.6kg$

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$W_n_e_t=4.224-3.424512$

$W_n_e_t=0.799488\approx 0.8J$

b)Generally K.E can be given mathematically as

$K.E= W_n_e_t$

Therefore

$K.E=0.8J$

c)Generally the equation for kinetic energy is mathematically represented by

$K.E=1/2mv^2$

$0.8=1/2mv^2$

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An equilibrium constant is not changed by a change in pressure <br> a. True<br> b. False

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Hi There! :)

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Answer:

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Explanation:

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