All categories

3 years ago

Can someone please help me I need it ASAP

Mathematics

1 answer:

VLD [36.1K]3 years ago

5 0

We're not supposed to help with exams. This isn't an exam, is it?

A(0)=202, A(37)=half that.

$A(t) = 202 (\frac 1 2)^{t/37}$

$A(100) = 202 (\frac 1 2)^{100/37} \approx 31.0$

Last choice.

You might be interested in

Y=15-4y what is the answer Y=___

Dominik [7]

Y=15 -4y
+4y +4y
5y=15
÷ ÷
5 5
y=3

6 0

3 years ago

The number of a countrys unemployed workers decreased from 3.2 million to 2.5 million last year. If the country's population rem

Sever21 [200]

More people have grown up or more people have found jobs

Hope this helps....
--------------------------------------------------------------------------------

5 0

3 years ago

MA = 8x – 2, mB = 2x – 8, and mC = 94 – 4x. List the sides of ABC in order from shortest to longest.

LUCKY_DIMON [66]

I hope this helps you

3 0

3 years ago

Question 3 of 10

iragen [17]

Answer:

Question 3 of 10 The answer should be 7

Step-by-step explanation:

The reason is because if it is out of 100 7/100 is still 7%

6 0

3 years ago

Susan threw a softball 42 years on her first try and 51 1/3 yard on her second try. How much farther did she throw the softball

Andru [333]

Answer:

28 feet farther than 1st ball.

Step-by-step explanation:

We have been given that Susan threw a softball 42 yards on her first try and $51\frac{1}{3}$ yard on her second try.

To find second ball is how much farther from the 1st ball, we will subtract 42 yards from $51\frac{1}{3}$ yards.

$\text{The second ball is farther from 1st ball}=51\frac{1}{3}\text{ yards}-42\text{ yards}$

$\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-42\text{ yards}$

Let us have a common denominator.

$\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-\frac{42*3}{3}\text{ yards}$

$\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-\frac{126}{3}\text{ yards}$

$\text{The second ball is farther from 1st ball}=\frac{154-126}{3}\text{ yards}$

$\text{The second ball is farther from 1st ball}=\frac{28}{3}\text{ yards}$

$\text{1 yard}=3\text{ feet}$

$\frac{28}{3}\text{ yards}=\frac{28}{3}\times 3\text{ feet}$

$\frac{28}{3}\text{ yards}=28\text{ feet}$

Therefore, Susan thrown the second ball 28 feet farther from the 1st ball.

7 0

3 years ago