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postnew [5]
3 years ago
15

Explain the centrifuging ​

Chemistry
1 answer:
Lynna [10]3 years ago
3 0

Answer:the force from spinning that moves things away from the center

Explanation: ap chem

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The gleaming metallic appearance of the Gateway Arch in St. Louis, Missouri, comes from the stainless steel used in its construc
omeli [17]

Answer:

the mole ratio of chromium to nickel atoms in the steel is 2.383

Explanation:

Given the data in the question;

Chromium  = 19% ( by mass )

Nickel = 9% ( by mass )

now, let the mass of the steel = 100 g

so mass of Chromium  = 19g

mass of nickel = 9g

We know that; Atomic mass of Cr is 52 g/mol, Atomic mass of Ni is 58.7 g/mol

Moles of Cr =  mass/atomic number = 19/52 mol

Moles of Ni =  mass/atomic number = 9/58.7 mol

The mole ratio of of Cr to Ni atom  will be;

⇒ Moles of Cr / Moles of Ni

= (19/52) / (9/58.7)

= 19×58.7 / 9×52

= 2.383

Therefore, the mole ratio of chromium to nickel atoms in the steel is 2.383

8 0
3 years ago
Which of the following will stay constant, no matter if the substance is in the solid, liquid, or gas state?
Hoochie [10]

Answer: Mass will Always stay constant.

5 0
3 years ago
4.00 g of sodium and 2.00 g of oxygen react according to the following balanced equation 4 Na + O2 → 2 Na2O Calculate the mass o
posledela
6.00g because it is a balanced equation
6 0
3 years ago
Gaseous butane, CH3(CH2)2CH, reacts with gaseous oxygen gas, O2, to produce gaseous carbon dioxide, CO2, and gaseous water, H2O.
weeeeeb [17]

Answer:

Percentage yield of carbon dioxide is 49.9%

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2CH3(CH2)2CH3 + 13O2 —> 8CO2 + 10H2O

OR

2C4H10 + 13O2 —> 8CO2 + 10H2O

Next, we shall determine the masses of butane and oxygen that reacted and the mass of carbon dioxide produced from the balanced equation. This is illustrated below:

Molar mass of butane C4H10 = (12×4) + (10×1)

= 48 + 10

= 58 g/mol

Mass of C4H10 from the balanced equation = 2 × 58 = 116 g

Molar mass of O2 = 16 × 2 = 32 g/mol

Mass of O2 from the balanced equation = 13 × 32 = 416 g

Molar mass of CO2 = 12 + (16×2)

= 12 + 32

= 44 g/mol

Mass of CO2 from the balanced equation = 8 × 44 = 352 g

Summary:

From the balanced equation above,

116 g of butane reacted with 416 g of oxygen to produce 352 g of carbon dioxide.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

116 g of butane reacted with 416 g of oxygen.

Therefore, 34.29 g of butane will react with = (34.29 × 416) / 116 = 122.97 g of oxygen.

From the calculation made above, we can see clearly that only 122.97 g out of 165.7 g of oxygen reacted completely with 34.29 g of butane. Therefore, butane is the limiting reactant and oxygen is the excess reactant.

Next, we shall determine the theoretical yield of carbon dioxide.

In this case, we shall use the limiting reactant because it will give the maximum yield of carbon dioxide as all of it is used up in the reaction.

The limiting reactant is butane and the theoretical yield of carbon dioxide can be obtained as follow:

From the balanced equation above,

116 g of butane reacted to produce 352 g of carbon dioxide.

Therefore, 34.29 g of butane will react to produce = (34.29 × 352) / 116 = 104.05 g of carbon dioxide.

Therefore, the theoretical yield of carbon dioxide is 104.05 g

Finally, we shall determine the percentage yield of carbon dioxide as follow:

Actual yield of carbon dioxide = 51.9 g

Theoretical yield of carbon dioxide = 104.05 g

Percentage yield of carbon dioxide =?

Percentage yield = Actual yield /Theoretical yield × 100

Percentage yield of carbon dioxide = 51.9 / 104.05 × 100

Percentage yield of carbon dioxide = 49.9%

7 0
3 years ago
In the equation C3H8 + O2 -> CO2 + H2O, what coefficient belongs in front of the O2 group?
tankabanditka [31]

Answer:

3

Explanation:

C3H8. + 5O2. ::: 3CO2. + 4H2O

4 0
3 years ago
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