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3 years ago

Please someone help ill give out the brainliest I will pleaseee just help

Chemistry

1 answer:

snow_lady [41]3 years ago

5 0

Answer:

have a great time at y avg be have a great time at all today I was going to answer restroom for spring break is over and over again and again and again and again and again and again your hhhha

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When a hydrogen atom makes the transition from the second excited state to the ground state (at -13.6 eV) the energy of the phot

viktelen [127]

Answer : The energy of the photon emitted is, -12.1 eV

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First we have to calculate the $'n^{th}'$ orbit of hydrogen atom.

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$E_n=-13.6\times \frac{Z^2}{n^2}ev$

where,

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Energy of n = 1 in an hydrogen atom:

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Energy of n = 2 in an hydrogen atom:

$E_3=-13.6\times \frac{1^2}{3^2}eV=-1.51eV$

Energy change transition from n = 1 to n = 3 occurs.

Let energy change be E.

$E=E_-E_3=(-13.6eV)-(-1.51eV)=-12.1eV$

The negative sign indicates that energy of the photon emitted.

Thus, the energy of the photon emitted is, -12.1 eV

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