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<u>Answer:</u> The amount of carbon dioxide gas produced in the reaction is 83.6 grams
<u>Explanation:</u>
As, some amount of oxygen gas is left after the reaction is completed. So, it is present in excess and is considered as an excess reagent.
Thus, carbon is considered as a limiting reagent because it limits the formation of product.
To calculate the number of moles, we use the equation:
.....(1)
Given mass of carbon = 22.8 g
Molar mass of carbon = 12 g/mol
Putting values in equation 1, we get:
The chemical equation for the reaction of carbon and oxygen gas follows:
By Stoichiometry of the reaction:
1 mole of carbon produces 1 mole of carbon dioxide gas
So, 1.9 moles of carbon will produce = of carbon dioxide gas
Now, calculating the mass of carbon dioxide from equation 1, we get:
Molar mass of carbon dioxide = 44 g/mol
Moles of carbon dioxide = 1.9 moles
Putting values in equation 1, we get:
Hence, the amount of carbon dioxide gas produced in the reaction is 83.6 grams
Answer:
The pair of arrows which represents the relationship of speeds of the two cars is;
The second option as shown in the attached drawing
Explanation:
The given parameters are;
The reading on the speedometer of one car = 20 m/s
The reading on the speedometer of the other car = 72 km/h = 20 m/s
The blue arrow = 20 m/s
Therefore, given that the speeds of both cars are equal (20 m/s = 72 km/h = 20 m/s), the pair of arrows that represent the relationship of speeds of the two cars is two equal length blue arrows which is the second option
The attached diagram showing the pair of arrows that represents the relationship of speeds of the two cars is drawn using Microsoft Visio.
